Answer:
a ave = ( v1x - v0x ) i/Δt + v1y j/Δt
Explanation:
Answer:
please specify you question well
<span>Kinematics is used in this problem. The mass does not matter here because the question is mass independent.
vi = 0
vf = x
d = ?
d = vi + 1/2 a t^2
d = 0 + 1/2 (9.8) (1.8)^2
d = 15.9 m (counting sig figs)</span>
I’m not too sure but maybe C?
Answer:
The minimum frequency is 702.22 Hz
Explanation:
The two speakers are adjusted as attached in the figure. From the given data we know that
=3m
=4m
By Pythagoras theorem

Now
The intensity at O when both speakers are on is given by

Here
- I is the intensity at O when both speakers are on which is given as 6

- I1 is the intensity of one speaker on which is 6

- δ is the Path difference which is given as

- λ is wavelength which is given as

Here
v is the speed of sound which is 320 m/s.
f is the frequency of the sound which is to be calculated.

where k=0,1,2
for minimum frequency
, k=1

So the minimum frequency is 702.22 Hz