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mamaluj [8]
3 years ago
15

Explain the qualifications that must be met for any vehicle to go in space.

Physics
2 answers:
Lubov Fominskaja [6]3 years ago
8 0

Answer: It must be able to handle a lot of pressure and heat

Explanation:

Shkiper50 [21]3 years ago
5 0

Ais 1+1is2 so you put 9x9 in 2+2 what the answer is your answer hope it help

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An object travels with velocity v = 4.0 meters/second and it makes an angle of 60.0° with the positive direction of the y-axis.
zhenek [66]

Answer:

2 m/s and -2 m/s

Explanation:

The object travels with an angle of

60.0°

with the positive direction of the y-axis: this means that it lies either in the 1st quadrant (positive x) or in the 2nd quadrant (negative x).

If it lies in the 1st quadrant, the value of vx (component of v along x direction) is:

v_x = v cos \theta = (4.0 m/s) cos 60.0^{\circ}=2 m/s

If it lies in the 2nd quadrant, the value of vx (component of v along x direction) is:

v_x = -v cos \theta = -(4.0 m/s) cos 60.0^{\circ}=-2 m/s

5 0
3 years ago
The free-fall acceleration at the surface of planet 1 is 26 m/s^2 . The radius and the mass of planet 2 are twice those of plane
valkas [14]

Answer:

13 m/s^2

Explanation:

The acceleration of gravity near the surface of a planet is:

g = MG / R^2

For planet 1, g = 26 m/s^2.

The gravity on planet 2 in terms of the mass and radius of planet 1 is:

g = (2M)G / (2R^2)

g = 1/2 MG / R^2

Since MG/R^2 = 26 m/s^2, then:

g = 13 m/s^2

6 0
3 years ago
An ideal gas is taken through a cyclic thermodynamic process through four steps. The amounts of heat given to the system in thes
Mashcka [7]

Answer:

\\  \\  \\  \\  \\ ....

6 0
2 years ago
What are wind and water erosion not likely to affect
zavuch27 [327]

Answer:

Tides, bodies of water

Explanation:

5 0
3 years ago
Read 2 more answers
As a person squeezes and applies pressure to the outside of a balloon, air particles inside
mixas84 [53]

The air particle inside the balloon will collide more with each other and the temperature inside the balloon will increase.

As a person squeezed and applies the pressure to the outside of a balloon, the air particle inside the balloon gains energy and collide with each other, the particle of the air also try leave the balloon surface will implies equal pressure on the wall of the balloon, as the pressure outside the balloon increase, the inside pressure will also increase.

7 0
3 years ago
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