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OLEGan [10]
3 years ago
7

An engineer is testing a large wind turbine that is used generating energy. Intially the large wind blades are locked in place a

nd not rotating. In a steady wind, the engineer releases the blades and they begin to rotate. She notes from the instruments that for the first 60 seconds the blades have a constant angular acceleration of 0.05rad/s2 . How many complete revolutions of the turbine occur during this time
Physics
2 answers:
soldier1979 [14.2K]3 years ago
5 0

Answer:

28 revolutions

Explanation:

Here we are going to use the accelerated angular motion formulas.

θ=wo*t+\frac{1}{2}*\alpha*t^2

because it starts from rest, wo=0

θ=\frac{1}{2}*(0.05rad/s^2)*(60s)^2

θ=180rad

The number of revolutions is given by:

N=\frac{180rad}{2*\pi\frac{rad}{rev}}=28.64rev

So the turbine completed 28 revolutions at that time.

emmasim [6.3K]3 years ago
4 0

Answer:

3 revolution in rad

Explanation:

angular acceleration α= rev/time

but α= 0.05rad/s

rev = α * time(in sec)

rev = 0.05 * 60

rev = 3rad/s

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prohojiy [21]

Answer: The weight of the air displaced by the balloon is less than the volume of the balloon.

Explanation:

A hot air balloon is a cloth wrap that contains several thousand cubic meters of air inside (a large volume of air). The burner heats the liquid propane to a gaseous state to generate a huge flame, which can reach more than 3 meters, thus heating the air mass inside the balloon. In this way,<u> its density is modified with respect to the air that surrounds it</u>, because the hot air is lighter than the outside air (less dense), causing the balloon to rise and float.

Now, if we know that the density of a body d is directly proportional to its mass m and inversely proportional to its volume V:

d=\frac{m}{V}

We can deduce that <u>by increasing the volume of the body, its density will decrease.</u>

This is proof of <em><u>Archimedes' Principle</u></em>:  

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4 0
3 years ago
Sayid made a chart listing data of two colliding objects. A 5-column table titled Collision: Two Objects Stick Together with 2 r
Alborosie

Answer:

6 m/s is the missing final velocity

Explanation:

From the data table we extract that there were two objects (X and Y) that underwent an inelastic collision, moving together after the collision as a new object with mass equal the addition of the two original masses, and a new velocity which is the unknown in the problem).

Object X had a mass of 300 kg, while object Y had a mass of 100 kg.

Object's X initial velocity was positive (let's imagine it on a horizontal axis pointing to the right) of 10 m/s. Object Y had a negative velocity (imagine it as pointing to the left on the horizontal axis) of -6 m/s.

We can solve for the unknown, using conservation of momentum in the collision: Initial total momentum = Final total momentum (where momentum is defined as the product of the mass of the object times its velocity.

In numbers, and calling P_{xi} the initial momentum of object X and P_{yi} the initial momentum of object Y, we can derive the total initial momentum of the system: P_{total}_i=P_{xi}+P_{yi}= 300*10 \frac{kg*m}{s} -100*6\frac{kg*m}{s} =\\=(3000-600 )\frac{kg*m}{s} =2400 \frac{kg*m}{s}

Since in the collision there is conservation of the total momentum, this initial quantity should equal the quantity for the final mometum of the stack together system (that has a total mass of 400 kg):

Final momentum of the system: M * v_f=400kg * v_f

We then set the equality of the momenta (total initial equals final) and proceed to solve the equation for the unknown(final velocity of the system):

2400 \frac{kg*m}{s} =400kg*v_f\\\frac{2400}{400} \frac{m}{s} =v_f\\v_f=6 \frac{m}{s}

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3 years ago
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Two balls of mass m1 and m2, with velocities v1 and v2 collide head on. Is there any way for both balls to have zero velocity af
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Answer:

Explanation:

As the final Kinetic energy is zero or less than initial kinetic energy, the collision must be inelastic.  

In Inelastic collision both the bodies must stick together as final velocity is zero for both the bodies.

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m_1v_1=m_2v_2

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To determine a waves' frequency, you must know the
kykrilka [37]
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