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OLEGan [10]
3 years ago
7

An engineer is testing a large wind turbine that is used generating energy. Intially the large wind blades are locked in place a

nd not rotating. In a steady wind, the engineer releases the blades and they begin to rotate. She notes from the instruments that for the first 60 seconds the blades have a constant angular acceleration of 0.05rad/s2 . How many complete revolutions of the turbine occur during this time
Physics
2 answers:
soldier1979 [14.2K]3 years ago
5 0

Answer:

28 revolutions

Explanation:

Here we are going to use the accelerated angular motion formulas.

θ=wo*t+\frac{1}{2}*\alpha*t^2

because it starts from rest, wo=0

θ=\frac{1}{2}*(0.05rad/s^2)*(60s)^2

θ=180rad

The number of revolutions is given by:

N=\frac{180rad}{2*\pi\frac{rad}{rev}}=28.64rev

So the turbine completed 28 revolutions at that time.

emmasim [6.3K]3 years ago
4 0

Answer:

3 revolution in rad

Explanation:

angular acceleration α= rev/time

but α= 0.05rad/s

rev = α * time(in sec)

rev = 0.05 * 60

rev = 3rad/s

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djverab [1.8K]

Answer:

capacitance of the capacitor = 0.18 μ  F

Explanation:

Area of the plate A = 0.063 m x 5.4 m = 0.3402 m²

distance between the plate d = 3.5 × 10–5 m

dielectric value for Teflon K = 2.1

capacitance of capacitor = ?

Formula for capacitance of parallel plate is as follows ,

C= \frac{K\epsilon_0 A}{d} (Where \epsilon_0 = 8.82 \times 10^-12\ \frac{F}{m} )

putting the values in the equation,

C = \frac{2.1\times8.82\times10^-12\times0.3402 }{3.5\times10^-5} =0.18\times 10^-6 =0.18 μ  F

4 0
3 years ago
According to Charles's law, for a fixed quantity of gas at constant pressure, which of the given quantities is constant? Accordi
Naddik [55]
Charles's <span>law is also known as the law of volumes explained the relation between the volume of gas and its temperature.

Charles's law states that: " At constant pressure, the volume of a certain mass of gas is directly proportional to its temperature in kelvin".
This means that:
V = T*constant
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Based on this, the correct choice is:
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7 0
3 years ago
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A wheel is rotating at 30.0 rpm. The wheel then accelerates uniformly to 50.0 rpm in 10.0 seconds. Determine the – a) rate of an
Mademuasel [1]

Answer:

The angular acceleration is 0.209\ rad/s^2

Explanation:

Given that,

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Angular velocity, \omega_{f} = 50.0\ rpm

Time t = 10.0 sec

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Using formula of angular acceleration

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\alpha=\dfrac{\omega_{f}-\omega_{i}}{\Delta t}

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Now, we change the angular velocity in rad/s.

\omega=20\times\dfrac{2\pi}{60}

\omega=2.09\ rad/s

\alpha=\dfrac{2.09}{10.0}

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3 years ago
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Answer:

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3 years ago
A small ball of mass 2.00 kilograms is moving at a velocity 1.50 meters/second. It hits a larger, stationary ball of mass 5.00 k
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The small ball has 2.25 joules of kinetic energy before the collision.
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