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3 years ago

An object has a mass of 25 kg. What is the force of gravity acting on the object?

Physics

1 answer:

aleksandrvk [35]3 years ago

5 0

Answer:

Explanation:

Because u don't know the gravity so u take that force and just put it in the gravity spot

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How can I solve the following statement?

Firlakuza [10]

Answer:

The net electric field at the midpoint is 6.85 x 10^7 N/C.

Explanation:

q = − 8.3 μC

q' = + 7.8 μC

d = 9.2 cm

d/2 = 4.6 cm

The electric field due to the charge q at midpoint is

$E = \frac{k q}{r^2}\\\\E = \frac{9\times 10^9\times 8.3\times 10^{-6}}{0.046^2}\\\\E = 3.53\times 10^7 N/C$ leftwards

The electric field due to the charge q' at midpoint is

$E' = \frac{k q}{r^2}\\\\E' = \frac{9\times 10^9\times 7.8\times 10^{-6}}{0.046^2}\\\\E' = 3.32\times 10^7 N/C$

The resultant electric field at mid point is

E'' = E + E' = (3.53 + 3.32) x 10^7 = 6.85 x 10^7 N/C

7 0

2 years ago

A vector has components Ax = 12.0 m and Ay= 5.00 m. What is the angle that vector A makes with the x-axis?a. 67.4ob. 32.6oc. 22.

antoniya [11.8K]

Answer:

C.22.6°

Explanation:

Ax = ACosθ,

A = Ax/Cosθ .....equ1

Ay = Asinθ,

A= Ay/sinθ .....equ 2

equate equation 1 and 2.

Ax/Cosθ = Ay/sinθ

Ax = 12.0 m, Ay= 5.00 m

12/Cosθ = 5/sinθ

θ = 22.6°

5 0

3 years ago

Heeeelllllllpppp I need this right now

dem82 [27]

Static friction

hope this helps

7 0

3 years ago

Read 2 more answers

At a country music festival, a band is playing at the end of a crowded

Anna11 [10]

Answer:

t=4.86s

Explanation:

To find the wavelength you use the following formula:

$v=\lambda f$

v: speed of sound = 343m/s

f: frequency = 400Hz

λ: wavelength of the sound

By doing λ the subject of the formula and replacing the values of f and v you obtain:

$\lambda=\frac{v}{f}=\frac{343m/s}{400Hz}=0.85m$

Now, to calculate the time that sound takes to reach the last row you use:

$t=\frac{d}{v}$

t: time

d: distance to the last row = 1947m

$t=\frac{1947m}{400Hz}=4.86s$

hence, the time is 4.86s

4 0

3 years ago

How much work is done when you push a crate horizontally with 150 N across a 13-m floor

Mila [183]

Work = (force) x (distance)

When a force of 150 N pushes through a distance of 13 meters,
it does

Work = (150 N) x (13 m) = 1,950 joules .

6 0

3 years ago