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2 years ago

An object has a mass of 25 kg. What is the force of gravity acting on the object?

Physics

1 answer:

aleksandrvk [35]2 years ago

5 0

Answer:

Explanation:

Because u don't know the gravity so u take that force and just put it in the gravity spot

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How would the body be affected if red blood cells and low levels of homoglobinHow would the

JulsSmile [24]

Low blood pressure. The person could faint and have an irregular heartbeat.

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2 years ago

A 60cm long string of an ordinary guitar is tuned to produce the note a4 (frequency 440hz) when vibrating in its fundamental mod

pishuonlain [190]

Answer:

0.78 m

Explanation:

The relationship between wavelength and frequency of a wave is given by

$v=f \lambda$

where

v is the speed of the wave

f is the frequency

$\lambda$ is the wavelength

For the sound wave in this problem, we have

$f=440 Hz$ is the frequency

v = 344 m/s is the speed of sound in air

Substituting into the equation and re-arranging it, we find the wavelength:

$\lambda=\frac{v}{f}=\frac{344 m/s}{440 Hz}=0.78 m$

8 0

2 years ago

Read 2 more answers

7. A particle is forced to move in a straight line path. It returns to the starting point after 10 s. The total distance covered

lutik1710 [3]

d. All three statements are true.

8 0

1 year ago

A uniform ladder 5.0 m long rests against a frictionless, vertical wall with its lower end 3.0 m from the wall. The ladder weigh

DiKsa [7]

Answer:(a)360N,(b)171N,(c)2.702m

Explanation:

(a)Maximum Friction Force = $\mu \left ( N\right )=0.4\times \left ( 740+160\right )$

=360 N

$cos\theta =\frac{3}{5}$

$sin\theta =\frac{4}{5}$

(b)Moment about Ground Point

$740\times 1\times cos\theta +2.5\times 160\times cos\theta -N_15sin\theta$

$N_1tan\theta =1140$

$N_1=171 N$

$N_1=f=171 N$

(c)

$740\times x\times cos\theta +2.5\times 160\times cos\theta -N_15sin\theta$

Here maximum friction force can be 360 N

Therefore $N_1=360 N$

Where x is the maximum distance moved by man along the ladder

$360\times 5\times \frac{4}{3}=740x+160\times 2.5$

740x=2000

x=2.702m

5 0

2 years ago

1. A car travels along a straight road to the east for 100 meters in 4 seconds, then go the west for 50 meters in 1 second.

Alla [95]

Answer:

a.Distance = 150 m

b. Displacement = 50 m

Time lapsed = 5 seconds

Explanation:

a. Distance is the change in the position of an object.

The distance covered by the car = 100 + 50

= 150 m

b. Since displacement is a vector quantity,

Displacement of the car = 100 - 50

= 50 m due east

c. Time elapsed is the time taken for the motion of the car starting from when its starts to when it stops.

Thus, the time elapsed = 4 + 1

= 5 seconds

4 0

2 years ago