<span>The answer is 62 u. The molecular mass of a molecule (Mr) is the sum of atomic masses (Ar) of its elements. Ar(Na) = 23 u. Ar(O) = 16 u. Therefore, the molecular mass of sodium oxide is 62 u: Mr(Na2O) = 2 * Ar(Na) + Ar(O) = 2 * 23 u + 16 u = 46 + 16 = 62 u.</span>
R = 1.4GΩ.
The relation between the resistance and the resistivity is given by the equation R = ρL/A, where ρ is the resistivity of a given material, L is the length and A is the cross-sectional area of the material.
To calculate the resistance of a wire of L = 2m, ρ = 49x10⁴Ω.m and A = 0.7mm² = 0.7x10⁻³m² we have to use the equation R = ρL/A.
R = [(49x10⁴Ω.m)(2m)/0.7x10⁻³m²
R = 98x10⁴Ω.m²/0.7x10⁻³m²
R = 1.4x10⁹Ω = 1.4GΩ
Answer:
-0.04194 V
Explanation:
= Number of turns in outer solenoid = 330
= Number of turns in inner solenoid = 22
= Current in inner solenoid = 0.14 A
= Rate of change of current = 1800 A/s
= Vacuum permeability =
r = Radius = 0.0115 m
Magnetic field is given by
The average magnetic flux through each turn of the inner solenoid is
Magnetic flux is given by
Mutual inductance is given by
The mutual inductance of the two solenoids is
Induced emf is given by
The emf induced in the outer solenoid by the changing current inthe inner solenoid is -0.04194 V
Length of the pendulum (l) = 2 m
Acceleration due to gravity = g = 9.8 m/s^2
For small amplitude, the pendulum will undergo simple harmonic motion.
Hence, the time period of the pendulum for small amplitude =
Now, plug the values of l and g
T =
T = 2 × 3.14 × 0.451
T = 2.83 seconds
Hence, the time period of the pendulum for small amplitude = 2.83 s
Answer:
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