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2 years ago

The sun, moon, planets and stars rise in the and set in the .

Physics

1 answer:

Masja [62]2 years ago

7 0

The sun, moon, planets and stars rise in the EAST and set in the WEST.

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A cat falls from a table of height 1.3 m. What is the impact speed of the cat? ( i want the answer NOT THE FORMULA)

telo118 [61]

The impact speed will be
v^2 = 2*9.8*1.3
v^2 = 25.48
v= 5.04 m/s

4 0

3 years ago

Read 2 more answers

A car travels 200m in 30 s and 400m in the next 90s. Whats the average speed?

VLD [36.1K]

Answer:

300m per minute or 5m per second

6 0

3 years ago

A virtual image is formed 17.0 cm from a concave mirror having a radius of curvature of 39.0 cm. (a) Find the position of the ob

Wittaler [7]

Explanation:

Image distance, v = -17 cm (-ve for virtual image)

Radius of curvature of concave mirror, R = 39 cm

Focal length, f = -19.5 cm (-ve for a concave mirror)

(a) Using mirror's formula as :

$\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}$

$\dfrac{1}{u}=\dfrac{1}{f}-\dfrac{1}{v}$

$\dfrac{1}{u}=\dfrac{1}{-19.5}-\dfrac{1}{(-17)}$

u = 132.6 cm

So, the object is placed 132.6 cm in front of the mirror.

(b) Magnification of the mirror, $m=\dfrac{-v}{u}$

$m=\dfrac{-17}{132.6}$

m = -0.128

Hence, this is the required solution.

7 0

3 years ago

A tank having a volume of 0.85 m 3 initially contains water as a two-phase liquid-vapor mixture at 260 o C and a quality of 0.7.

Keith_Richards [23]

Answer:=14,160 kJ

Explanation: Let m1 and m2 be the initial and final amounts of mass within the tank, respectively. The steam properties are listed in the table below

Specific Internal SpecificTemp Pressure Volume Energy Enthalpy Quality Phase

C MPa m^3/kg kJ/kg kJ/kg

1 260 4.689 0.02993 2158 2298 0.7 Liquid Vapor Mixture

2 260 4.689 0.0422 2599 2797 1 Saturated Vapor

The mass initially contained in the tank is m1 = V/v1

m1 =0.85 m^3 /0.02993 m^3 /kg

= 28.4 kg

The mass finally contained in the tank is

m2 =V2/v

= 0.85 m^3 /0.0422 m^3 /kg

= 20.14 kg

The heat transfer is then

Qcv = m2u2 − m1u1 − he(m2 − m1)

Qcv = (20.14)(2599) − (28.4)(2158) − (2797)(20.14 − 28.4) = 14,160 kJ

4 0

3 years ago

Two circular holes, one larger than the other, are cut in the side of a large water tank whose top is open to the atmosphere. Ho

lidiya [134]

Answer: $\frac{r_1}{r_2}=1.565$

Explanation:

Given

two holes are made with different sizes

Hole 1 is large in size and hole 2 is small

If the volume flow rate of water is same for both the hole then small hole must be below the large hole because for same flow rate, velocity of water is large while cross-sectional area is small so it compensate to give same flow for both the holes.

Now for radius apply Bernoulli's theorem at hole 1 and 2

$P_1+\rho gh_1=P_{atm}+\frac{1}{2}\rho v_1^2$

$P_2+\rho g6h_2=P_{atm}+\frac{1}{2}\rho v_2^2$

if hole 1 is h distance below water surface then $h_2=6h$

and $P_1=P_2=P_{atm}$

Also $v_1=\sqrt{2gh}$

$v_2=\sqrt{2g(6h)}$

and $Q=A_1v_1=A_2v_2$

$A=\pi r^2$

thus $\dfrac{r_1}{r_2}=\sqrt{\dfrac{v_2}{v_1}}$

$\dfrac{r_1}{r_2}=\sqrt{\dfrac{\sqrt{6h}}{\sqrt{h}}}$

$\frac{r_1}{r_2}=1.565$

5 0

2 years ago

The sun, moon, planets and stars rise in the ____ and set in the ____.

The sun, moon, planets and stars rise in the and set in the .