Suppose a flagellum is rotating at a constant rps (revolution per second). What is the angular displacement of the flagellum in
1 answer:
Answer:
1794.47 radian.
Explanation:
Suppose a flagellum is rotating at a constant 952 rps (revolution per second). What is the angular displacement of the flagellum in 0.3seconds? (report your answer in SI units)
Let us suppose that a flagellum is rotating at a constant 952 revolution per second.
Firstly, we will convert 952 revolution per second to radian per second as follows :
952 revolution per second = 2π × 952 rad/s
=5981.592 rad/s
The angular displacement is given by the expression as follows :
So, the angular displacement of the flagellum in 0.3 seconds is 1794.47 radian.
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Answer:
a) Time = 2.67 s
b) Height = 35.0 m
Explanation:
a) The time of flight can be found using the following equation:
(1)
Where:
: is the final position in the horizontal direction = 80 m
: is the initial position in the horizontal direction = 0
: is the initial velocity in the horizontal direction = 30 m/s
a: is the acceleration in the horizontal direction = 0 (the stone is only accelerated by gravity)
t: is the time =?
By entering the above values into equation (1) and solving for "t", we can find the time of flight of the stone:
b) The height of the hill is given by:
Where:
: is the final position in the vertical direction = 0
: is the initial position in the vertical direction =?
: is the initial velocity in the vertical direction =0 (the stone is thrown horizontally)
g: is the acceleration due to gravity = 9.81 m/s²
Hence, the height of the hill is:
I hope it helps you!