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vitfil [10]
3 years ago
11

Suppose a flagellum is rotating at a constant rps (revolution per second). What is the angular displacement of the flagellum in

seconds?
Physics
1 answer:
IgorLugansk [536]3 years ago
5 0

Answer:

1794.47 radian.

Explanation:

Suppose a flagellum is rotating at a constant 952 rps (revolution per second). What is the angular displacement of the flagellum in 0.3seconds? (report your answer in SI units)

Let us suppose that a flagellum is rotating at a constant 952 revolution per second.

Firstly, we will convert 952 revolution per second to radian per second as follows :

952 revolution per second = 2π × 952 rad/s

=5981.592 rad/s

The angular displacement is given by the expression as follows :

\theta=\omega t\\\\\theta=5981.592\times 0.3\\\\\theta=1794.47\ \text{rad}

So, the angular displacement of the flagellum in 0.3 seconds is 1794.47 radian.

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77julia77 [94]
The answer is D. 44 miles

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Then we have 2x + 16 = 72
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The result is then D because </span></span>
28 + 16 = 44.
8 0
3 years ago
If you toss a ball vertically upward in a uniformly moving train, it returns to its starting place. Will it do the same if the t
gogolik [260]

Answer:No

Explanation:

No

As the train is accelerating so train velocity will be more as compared to the ball  and thus will cover more distance as compared to the ball.

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3 0
3 years ago
C: Calculate the kinetic energy of a car with a mass of 1563 kilograms that is traveling at 42 kilometers per hour.
kkurt [141]

Hello!

C. KE ≈ 9120.105 J

D. m = 151.45 kg

Question C:

Calculate kinetic energy using the formula:

KE = \frac{1}{2}mv^{2}

Substitute in the given mass. We have to convert kilometers to meters in order to solve.

\frac{42km}{1hr} * \frac{1hr}{3600sec} *\frac{1000m}{1km} = 11.67 m/s

Use the equation above:

KE = 1/2(1563)(11.67)

KE ≈ 9120.105 J

Question D:

Plug in the given Kinetic Energy and velocity to solve. Convert kilometers/hour to meters/second:

\frac{7km}{1hr} * \frac{1hr}{3600sec} *\frac{1000m}{1km} = 1.94 m/s

KE = \frac{1}{2}mv^{2}

285 = 1/2(m)(1.94²)

570 = (1.94²)m

151.45kg = m

6 0
3 years ago
A 5kg object accelerates from 3m/s to 7m/s in 5 seconds. Calculate the force required
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Answer:

4N

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