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amm1812
3 years ago
9

In the standing waves experiment, the string has a mass of 31.2 g and a length of 0.7 m. The string is connected to a mechanical

wave generator that produce standing waves with frequency of f. The other end of the string is connected to a mass holder (mholder = 50.0 g) that carries a weight of 5.00x10^2 g. Calculate the linear density of the string.
Physics
1 answer:
mestny [16]3 years ago
7 0

Answer:

linear density of the string = 4.46 × 10⁻⁴ kg/m

Explanation:

given,

mass of the string = 31.2 g

length of string = 0.7 m

linear density of the string = \dfrac{mass\ of\ string}{length}

linear density of the string = \dfrac{31.2\times 10^{-3}\ kg}{0.7\ m}

linear density of the string = 44.57 × 10⁻³ kg/m

linear density of the string = 4.46 × 10⁻⁴ kg/m

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Jason launches a model rocket with a mass of 2.0 kg from his spring-powered rocket launcher with a spring constant of 800 N/m. H
Arada [10]

Answer:

121 Joules

6.16717 m

Explanation:

m = Mass of the rocket = 2 kg

k = Spring constant = 800 N/m

x = Compression of spring = 0.55 m

Here, the kinetic energy of the spring and rocket will balance each other

\frac{1}{2}mu^2=\frac{1}{2}kx^2\\\Rightarrow u=\sqrt{\frac{kx^2}{m}}\\\Rightarrow u=\sqrt{\frac{800\times 0.55^2}{2}}\\\Rightarrow u=11\ m/s

The initial velocity of the rocket is 11 m/s = u.

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s² = g

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-11^2}{2\times -9.81}\\\Rightarrow s=6.16717\ m

The maximum height of the rocket will be 6.16717 m

Potential energy is given by

P=mgh\\\Rightarrow P=2\times 9.81\times \frac{0^2-11^2}{2\times -9.81}\\\Rightarrow P=121\ J

The potential energy of the rocket at the maximum height will be 121 Joules

5 0
3 years ago
4. The bar has cross-sectional area A and modulus of elasticity E. If an axial force F directed toward the right is applied at C
aniked [119]

Answer:

a)  ΔL/L = F / (E A),  b)   L_{f} = L (1 + L F /(EA) )

Explanation:

Let's write the formula for Young's module

     E = P / (ΔL / L)

Let's rewrite the formula, to have the pressure alone

    P = E ΔL / L

The pressure is defined as

    P = F / A

Let's replace

   F / A = E ΔL / L

   F = E A ΔL / L

   ΔL / L = F / (E A)

b) To calculate the elongation we must have the variation of the length, so the length of the bar must be a fact. Let's clear

    ΔL = L [F / EA]

    L_{f} -L = L (F / EA)

    L_{f} = L + L (F / EA)

    L_{f} = L (1 + L (F / EA))

4 0
3 years ago
Carlos is baking a cake. The last step in the directions is to put the cake batter in the oven. Why does Carlos need to put the
Schach [20]

Answer:

it's d

Explanation:

have you ever baked a cake? Everytime you put cake batter into the oven, it takes a few hours for it to start turning into cake.

4 0
3 years ago
Read 2 more answers
The equatorial diameter of earth is 7928 miles. If a mile equals 1.609 km, what is the earth's diameter in kilometers? in centim
tangare [24]

diameter of earth in miles= 7928 miles

1 mile = 1.609 km

diameter of earth in km= 7928*1.609

                                         =12,756.152 km

Hope it helped u, pls thank if u find this helpful

and don't forget to put this answer as the brainliest.

^_^.

7 0
3 years ago
Two inductors, L1 and L2, are in parallel. L1 has a value of 25 mH and L2 a value of 50 mH. The parallel combination is in serie
Bond [772]

Answer:

Explanation:

For parallel inductors ,

\frac{1}{L_R} = \frac{1}{L_1} +\frac{1}{L_2}

\frac{1}{L_R} =\frac{1}{25} +\frac{1}{50}

L_R=16.67 mH.

For series combination

Total inductance

= 16.67 + 20

= 36.67 mH .

reactance of total inductance at 300 kHz

= ωL_{total} where ω is angular frequency

= 2πfL_{total}

= 2 x 3.14 x 300 x 10³ x 36.67 x 10⁻³

= 69.1 x 10³ ohm

Total rms current = Vrms / reactance

= 60 / 69.1 x 10³ A

= .87 x 10⁻³ A

= .87 mA

7 0
2 years ago
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