A ball of mass of 0.5kg is dropped from a height of 2m.
1 answer:
Answer:
6.3m/s
Explanation:
Given parameters:
Mass of the ball = 0.5kg
Height = 2m
Unknown:
Velocity when the ball hits the ground = ?
Solution:
Since the potential energy is transformed into kinetic energy;
P.E = K.E
mgh = m v²
cancelling m;
gh = v²
v² = 2gh
v = √2gh
Insert the parameters and solve;
v = √2gh = √ 2 x 9.8 x 2 = 6.3m/s
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Answer:
The minimum speed =
Explanation:
The minimum speed that the rocket must have for it to escape into space is called its escape velocity. If the speed is not attained, the gravitational pull of the planet would pull down the rocket back to its surface. Thus the launch would not be successful.
The minimum speed can be determined by;
Escape velocity =
where: G is the universal gravitational constant, M is the mass of the planet X, and R is its radius.
If the appropriate values of the variables are substituted into the expression, the value of the minimum speed required can be determined.