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jekas [21]
3 years ago
14

A satellite in circular orbit around the Earth moves at constant speed. This orbit is maintained by the force of gravity between

the Earth and the satellite, yet no work is done on the satellite. How is this possible?
a. No work is done if there is no contact between objects.
b. No work is done because there is no gravity in space.
c. No work is done if the direction of motion is perpendicular to the force.
d. No work is done if objects move in a circle.
Physics
1 answer:
scoundrel [369]3 years ago
3 0

Answer:

C. No work is done if the direction of motion is perpendicular to the force.

Explanation:

We know that work is the dot product of force and displacement.

Let's take the angle between the force and the displacement = θ

W= F . d cosθ

F=Force  , d=Displacement  

If θ = 0° then W= F.d

If θ = 90° then W= 0

So we can say that when force is perpendicular to the displacement then the work done by force will be zero.

Therefore the answer is C.

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Two long, straight parallel wires are placed 38 cm apart, one above the other. The top and bottom wires are carrying currents 4.
ElenaW [278]

Answer:

The force per unit length (N/m) on the top wire is 16.842 N/m

Explanation:

Given;

distance between the two parallel wire, d = 38 cm = 0.38 m

current in the first wire, I₁ = 4.0 kA

current in the second wire, I₂ = 8.0 kA

Force per unit length, between two parallel wires is given as;

\frac{F}{L} = \frac{\mu_oI_1I_2 }{2\pi d }

where;

μ₀ is constant = 4π x 10⁻⁷ T.m/A

Substitute the given values in the above equation and calculate the force per unit length

\frac{F}{L} = \frac{\mu_oI_1I_2 }{2\pi d } = \frac{4\pi *10^{-7}*4000*8000 }{2\pi *0.38} = 16.842 \ N/m

Therefore, the force per unit length (N/m) on the top wire is 16.842 N/m

4 0
3 years ago
A rope of total mass m hnd length L is suspended vertically with an object of mass M suspended from the lower end. Find an expre
pantera1 [17]

Answer:

Part a)

v = \sqrt{xg + \frac{MLg}{m}}

Part b)

t = 12 s

Explanation:

Part a)

Tension in the rope at a distance x from the lower end is given as

T = \frac{m}{L}xg + Mg

so the speed of the wave at that position is given as

v = \sqrt{\frac{T}{\mu}}

here we know that

\mu = \frac{m}{L}

now we have

v = \sqrt{\frac{ \frac{m}{L}xg + Mg}{m/L}

v = \sqrt{xg + \frac{MLg}{m}}

Part b)

time taken by the wave to reach the top is given as

t = \int \frac{dx}{\sqrt{xg + \frac{MLg}{m}}}

t = \frac{1}{g}(2\sqrt{xg + \frac{MLg}{m}})

t = \frac{2}{9.8}(\sqrt{(39.2\times 9.8) + \frac{8(39.2)(9.8)}{1}})

t = 12 s

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3 years ago
According to the "Future Potential Source #2: Wind" article, what natural resource does wind power free up
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3 years ago
What is the momentum of a 950 kg car moving at 10.0 m/s?
pentagon [3]

Answer:

<h3>The answer is 9500 kgm/s</h3>

Explanation:

The momentum of an object can be found by using the formula

<h3>momentum = mass × velocity</h3>

From the question

mass = 950 kg

velocity = 10.0 m/s

We have

momentum = 950 × 10

We have the final answer as

<h3>9500 kgm/s</h3>

Hope this helps you

8 0
3 years ago
Read 2 more answers
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