The correct answer would be b
Do you have a picture of the table??
Answer:
353.
Step-by-step explanation:
you have to subtract
Answer:
a) Initial (Base) a
= 30000
b) the monthly payment needs to $150
Step-by-step explanation:
Given the data in the question;
a. Give a recursive definition for a,. including the recurrence relation and the base case.
the annual interest on the loan is 6% compounded monthly;
⇒ i = 6% / 12
i = 0.5%
so, the recurrence relation is a
= a
( 1 + i/100) - 600
Here Initial (Base) a
= 30000
b) Suppose that the borrower would like a lower monthly payment. How large does the monthly payment need to be to ensure that the amount owed decreases every month
Let p be the required monthly payment,
then the condition will be; a
≤ a![_{n-1}](https://tex.z-dn.net/?f=_%7Bn-1%7D)
a
( 1 + i/100) - p ≤ a![_{n-1}](https://tex.z-dn.net/?f=_%7Bn-1%7D)
a
( 1 + i/100) - a
≤ p
a
( 1 + i/100 - 1) ≤ p
a
( i/100 ) ≤ p
a
≤ p ( 100/i )
a
≤ p ( 100/0.5 )
a
≤ p (200)
we know that; a
= 30000
so
30000 ≤ p (200)
p ≤ 30000 / 200
p ≤ 150
Therefore, the monthly payment needs to $150
9514 1404 393
Answer:
x = 18
Step-by-step explanation:
Add the opposite of the constant (-5), and multiply by the inverse of the coefficient of x (2/3).
![\dfrac{2}{3}x -5=7\\\\\dfrac{2}{3}x=12 \qquad\text{add 5}\\\\x=\dfrac{3}{2}\cdot 12 \qquad\text{multiply by $\dfrac{3}{2}$}\\\\ \boxed{x=18}](https://tex.z-dn.net/?f=%5Cdfrac%7B2%7D%7B3%7Dx%20-5%3D7%5C%5C%5C%5C%5Cdfrac%7B2%7D%7B3%7Dx%3D12%20%5Cqquad%5Ctext%7Badd%205%7D%5C%5C%5C%5Cx%3D%5Cdfrac%7B3%7D%7B2%7D%5Ccdot%2012%20%5Cqquad%5Ctext%7Bmultiply%20by%20%24%5Cdfrac%7B3%7D%7B2%7D%24%7D%5C%5C%5C%5C%20%5Cboxed%7Bx%3D18%7D)