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3 years ago

Compare and contrast mechanical waves to electromagnetic waves

2 answers:

6 0

Answer:Electromagnetic waves are waves that have no medium to travel whereas mechanical waves need a medium for its transmission. Electromagnetic waves travel in a vacuum whereas mechanical waves do not. ... While an electromagnetic wave is called just a disturbance, a mechanical wave is considered a periodic disturbance.

Explanation:

dusya [7]3 years ago

3 0

Electromagnetics are a soft metal core made into a magnet by the passage of electric current through a coil surrounding it.
Mechanical waves are a wave that is an oscillation of matter, and therefore transfers energy through a medium.

Brainiest plz

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Hello, I need help. Due right now

ryzh [129]

Answer: See below

Explanation:

$\\ \mathrm{Given:} \\\mathrm{Mass \ of \ first \ car}$\left(m_{1}\right)=1383 \mathrm{~kg}$ \\ Velocity $\left(\overrightarrow{V_{1}}\right)=-11.2\ {\math} \mathrm{m} / \mathrm{s}$\\ Mass of second car -$\left(m_{2}\right)=1732 \mathrm{~kg}$\\ Velocity $\left(\vec{v}_{2}\right)=31.3 {\math} \mathrm{m} / \mathrm{s}$$

$m_{1} \vec{v}_{1}+m_{2} \vec{v}_{2}=\left(m_{1}+m_{2}\right) \vec{v} \\1383(-11.2 {\math})+1732(31.3 {\math}) \\=(1383+1732) \vec{v} \\-15489.6 {\math}+54211.6 {\math}=3115 \vec{v} \\ \vec{v}=(17.4 {\math}-4.972 {\math}) \ \mathrm{m/s}$

$\text { So magnitude } \vec{|v|} =\sqrt{(17.4)^{2}+(-4.972)^{2}} \\ =\sqrt{327.605} \\ =18.099 \mathrm \ {m/s} \\$

$\text { Direction } \\\theta=\tan ^{-1}\left(\frac{-4.972}{17.4}\right) \\\theta=-15.945^{\circ}\end{gathered}$

Therefore, both cars move with a velocity of 18.099 m/s in the direction of 15.945° downward from the x-axis (east)

7 0

3 years ago

Read 2 more answers

Don't take your heart rate with your thumb because the thumb has it's own pulse.

pogonyaev

Explanation:

yeah that's true.........

6 0

3 years ago

Read 2 more answers

g 1. Water flows through a 30.0 cm diameter water pipe at a speed of 3.00 m/s. All of the water in the pipe flows into a smaller

levacccp [35]

Answer:

a) v₂ = 30 m/s

b) m₁ = 12600 kg

c) m₂ = 12600 kg

Explanation:

Using the continuity equation:

$A_1v_1 = A_2v_2$

where,

A₁ = Area of inlet = π(0.15 m)² = 0.07 m²

A₂ = Area of outlet = π(0.05 m)² = 0.007 m²

v₁ = speed at inlet = 3 m/s

v₂ = speed at outlet = ?

Therefore,

$(0.07\ m^2)(3\ m/s)=(0.007\ m^2)v_2\\\\v_2 = \frac{0.21\ m^3/s}{0.007\ m^2}$

v₂ = 30 m/s

$m_1 = \rho A_1v_1t$

where,

m₁ = mass of water flowing in = ?

ρ = density of water = 1000 kg/m³

t = time = 1 min = 60 s

Therefore,

$m_1 = (1000\ kg/m^3)(0.07\ m^2)(3\ m/s)(60\ s)\\$

m₁ = 12600 kg

$m_1 = \rho A_1v_1t$

where,

m₂ = mass of water flowing out = ?

ρ = density of water = 1000 kg/m³

t = time = 1 min = 60 s

Therefore,

$m_2 = (1000\ kg/m^3)(0.007\ m^2)(30\ m/s)(60\ s)\\$

m₂ = 12600 kg

7 0

3 years ago

Suppose a soccer player kicks the ball from a distance 29 m toward the goal. find the initial speed of the ball if it just passe

Rudik [331]

The ball's vertical velocity at the time it just passes over the goal is 0 m/s. Its initial vertical velocity is unknown and we denote it by $v\sin39^\circ$ , where $v$ here is the ball's initial speed. Vertically, the only force acting on the ball is gravity, which attributes a downward acceleration of 9.8 m/s^2. We expect the maximum height achieved by the ball to be 2.4 m, so we can find the initial speed by solving

$\left(0\,\dfrac{\mathrm m}{\mathrm s}\right)^2-\left(v\sin39^\circ\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)(2.4\,\mathrm m)$

$\implies v=11\,\dfrac{\mathrm m}{\mathrm s}$

6 0

3 years ago

Once silicon burning begins to fuse iron in the core of a high-mass main-sequence star, it only has a few ________ left to live.

dmitriy555 [2]

Answer must be:

a few days left to live.

3 0

3 years ago