The mass m of the object = 5.25 kg
<h3>Further explanation</h3>Given
k = spring constant = 3.5 N/cm
Δx= 30 cm - 15 cm = 15 cm
Required
the mass m
Solution
F=m.g
Hooke's Law
F = k.Δx
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1 answer:
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Hello!
Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton force is applied to it.
Data:
Hooke represented mathematically his theory with the equation:
F = K * Δx
On what:
F (elastic force) = 2 N
K (elastic constant) = 4 N/cm
Δx (deformation or elongation of the elastic medium or distance from a spring) = ?
Solving:
simplify by 2
Answer:
B.) 1/2 cm
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Answer:
The Balmer series refers to the spectral lines of hydrogen, associated to the emission of photons when an electron in the hydrogen atom jumps from a level to the level
.
The wavelength associated to each spectral line of the Balmer series is given by:
where is the Rydberg constant for hydrogen, and where
is the initial level of the electron that jumps to the level n = 2.
The first few spectral lines associated to this series are withing the visible part of the electromagnetic spectrum, and their wavelengths are:
656 nm (red, corresponding to the transition )
486 nm (green, )
434 nm (blue, )
410 nm (violet, )
All the following lines lie in the ultraviolet part of the spectrum. The limit of the Balmer series, corresponding to the transition , is at 364.6 nm.