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hammer [34]
3 years ago
12

A force ModifyingAbove Upper F With right-arrow equals left-parenthesis c x minus 3.00 x squared right-parenthesis ModifyingAbov

e i With ˆ acts on a particle as the particle moves along an x axis, with ModifyingAbove Upper F With right-arrow in newtons, x in meters, and c a constant. At x = 0 m, the particle's kinetic energy is 20.0 J; at x = 2.00 m, it is 10.0 J. Find c.
Physics
1 answer:
Svetllana [295]3 years ago
8 0

Answer:

c= - 1

Explanation:

Given that

F=c x - 3 x²

We know that

Acceleration a

a=v\dfrac{dv}{dx}

F=mv\dfrac{dv}{dx}=cx-3x^2

\int_{v_o}^{v}mv{dv}=\int_{0}^{2}(cx-3x^2)dx

\left [m\dfrac{v^2}{2}\right ]^v_{v_o}=\left [\dfrac{cx^2}{2}-3\dfrac{x^3}{3} \right ]^2_0

\dfrac{mv^2}{2} -\dfrac{mv_o^2}{2} =\dfrac{c\times 2^2}{2}-{2^3}

10 - 20 = 2c - 8

-10+8 = 2c

c= - 1

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