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Inessa05 [86]
4 years ago
10

The fan blades suddenly experience an angular acceleration of 2 rad/s2. If the blades are rotating with an initial angular veloc

ity of 4 rad/s, determine the magnitude of the acceleration of point P when the blades have turned 2 revolutions. Ch16Prob4
a.115.95 ft/s^2
b.116 ft/s^2
c.0ft/s^2
d.3.5 ft/s^2
Engineering
1 answer:
madreJ [45]4 years ago
5 0

Answer:

Option B

116 ft/s^{2}

Explanation:

\theta=2 rev=2(2\pi)=4\pi

\alpha \theta=0.5(\omega_f^{2}-\omega_i^{2})

\alpha (4\pi)= 0.5(\omega_f^{2}-\omega_i^{2})

\alpha (8\pi)= (\omega_f^{2}-\omega_i^{2})

(2) (8\pi)= (\omega_f^{2}-\omega_i^{2})

(2) (8\pi)= (\omega_f^{2}-4^{2})

\omega_f=8.14 rads/s

v=r\omega=1.75*8.14=14.245 ft/s

Centripetal acceleration =\omega_f^{2} r=8.14^{2}*1.75=115.95 ft/s^{2}

Tangential component=dr=2*1.75=3.5

Resultant=\sqrt{3.5^{2}+115.95^{2}}\approx 116 ft/s^{2}

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Answer:

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<u>Explanation:</u>

The question follows Bernoulli's equation

P1 + 1/2 ρ V1² = P2 + 1/2 ρ V2²

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V2 = 60 X 5280 / 3600 = 88 ft/s

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P2 = 14.66 psi

Therefore, the pressure at the point on the roof where the speed is 60mph is 14.66 psi

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