A motor cycle is moving up an incline of 1 in 30 at a speed of 80 km/h,and then suddenly the engine shuts down.The tractive resi
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The question is incomplete. The complete question is :
The solid rod shown is fixed to a wall, and a torque T = 85N?m is applied to the end of the rod. The diameter of the rod is 46mm .
When the rod is circular, radial lines remain straight and sections perpendicular to the axis do not warp. In this case, the strains vary linearly along radial lines. Within the proportional limit, the stress also varies linearly along radial lines. If point A is located 12 mm from the center of the rod, what is the magnitude of the shear stress at that point?
Solution :
Given data :
Diameter of the rod : 46 mm
Torque, T = 85 Nm
The polar moment of inertia of the shaft is given by :
J = 207.6
So the shear stress at point A is :
Therefore, the magnitude of the shear stress at point A is 4913.29 MPa.
Answer:
A) energy loss E = pgQtH
Where p = density in kg/m3
g = gravity acceleration in m/s2
Q = flow rate in m3/s
t = time taken for flow in sec
H = height of flow in m
B) power required to run pump;
P = pgQH
Explanation:
Detailed explanation and calculation is shown in the image below
Answer:
The answer is below
Explanation:
1) The synchronous speed of an induction motor is the speed of the magnetic field of the stator. It is given by:
2) The speed of the rotor is the motor speed. The slip is given by:
3) The frequency of the rotor is given as:
4) At standstill, the speed of the motor is 0, therefore the slip is 1.
The frequency of the rotor is given as: