A motor cycle is moving up an incline of 1 in 30 at a speed of 80 km/h,and then suddenly the engine shuts down.The tractive resi
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Answer:
note:
solution is attached due to error in mathematical equation. please find the attachment
Answer:
HV = 372.4 KGf/mm^2
Explanation:
given data:
minimum tensile strength = 1240 MPa
we knwo that and brinell hardness number (HB} relation given as
1) relation betwen H.B and Rockwell is
2) relation between HB and Vickers hardnes HV is given as
HV = 372.4 KGf/mm^2
This question is incomplete, its missing an image which will be uploaded along this Answer.
Answer:
the normal component of force F_n is F((√(r²-s²)) / r)
the tangential component of force F_t is F(s/r)
Explanation:
Given the data in the image;
from the free body diagram, we write the expression for ∅
sin∅ = s/r
cos∅ = (√(r²-s²)) / r
now expression for normal component of force is;
F_n = Fcos∅
we substitute
F_n = F((√(r²-s²)) / r)
Therefore, the normal component of force F_n is F((√(r²-s²)) / r)
Also for force F_t
F_t = Fsin∅
we substitute
F_t = F(s/r)
Therefore, the tangential component of force F_t is F(s/r)
