Answer:
Check the explanation
Explanation:
Single Unit Truck ESAL = 43.38 + 5.16 = 48.54
Semi Unit Truck ESAL = 43.38+ 6.00+7.4 = 56.78
So total ESAL's during design life = (400*48.54 + 350*56.78)*365*10/18000 = (19416+19873)*3650= 3939
Kindly check the attached image
Here
Reliability = 95% = 0.95, therefore ZR = -1.645, S0 = 0.4, MR = 18
Delta PSI = 4.2-2.5= 1.7
Resilient Modulus = 18000 psi, So MR = 18
Assume SN = 3.0 for flexible pavements
There W18 calculates to 0.26807
So
log10 (3939) = 9.36*log10(SN+1) -.2/(.4+1094/(SN+1)5.19)) -6.01
Structural Number SN = a1*d1 + a2*d2 *m2 +a2*d3 *m3
= a1*d1 + a2*d2 +a2*d3
Answer:
TRUE
Explanation:
Polymers can be natural as well as synthetic
The polymer which are found in nature are called natural polymer tease polymer are not synthesized, they are found in nature
Example of natural polymers is cellulose, proteins etc
On the other hand synthetic polymers are not found in nature they are synthesized in market
There are many example of synthetic polymer
Example : nylon, Teflon etc
So it is a true statement
Answer:
The answer is the <u>strain gauges.
</u>
Explanation:
Inspection systems work or are performed to measure the characteristics of a product, to verify if it meets specified requirements, all using benchmarks and test equipment.
The strain gauges are part of the test equipment used for inspection. These are sensors that measure deformation, pressure and load in resistance tests of materials.
Answer:
hello your question lacks the required question attached below is the missing diagram
Forces in GJ = -4.4444 i.e. 4.4444 tons
Forces in IG = 15.382 tons ( T )
Explanation:
Forces in GJ = -4.4444 i.e. 4.4444 tons
Forces in IG = 15.382 tons ( T )
attached below is the detailed solution
Answer:
When water is surrounding T_s = 34.17 degree C
When air surrounding T_S = 1434.7 degree C
from above calculation we can conclude that air is less effective than water as heat transfer agent
Explanation:
Given data:
length = 300 mm
Outer diameter = 30 mm
Dissipated energy = 2 kw = 2000 w
Heat transfer coefficient IN WATER = 5000 W/m^2 K
Heat transfer coefficient in air = 50 W/m^2 K
we know that 
From newton law of coding we have
is surface temp.
T - temperature at surrounding
![P = hA(T_s - T_{\infity})[tex]\frac{P}{\pi hDL} = (T_s - T_{\infity})](https://tex.z-dn.net/?f=P%20%3D%20hA%28T_s%20-%20%20T_%7B%5Cinfity%7D%29%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Cfrac%7BP%7D%7B%5Cpi%20hDL%7D%20%3D%20%20%28T_s%20-%20%20T_%7B%5Cinfity%7D%29)
solving for[/tex] T_s [/tex] w have
When air is surrounding we have
from above calculation we can conclude that air is less effective than water as heat transfer agent
