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umka2103 [35]
3 years ago
14

As a space shuttle climbs, _______

Physics
2 answers:
n200080 [17]3 years ago
4 0
Rocket fuel will and smoke will emit from the thrusters.
lesya692 [45]3 years ago
3 0

ITS MASS  DECREASES

Fuel is released and the rocket takes off into space.

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In 0.60 seconds, a projectile goes from 0 to 610 m/s. What is the acceleration of the projectile?
IceJOKER [234]

Answer: a=1016.66 m/s^{2}

Explanation:

Acceleration a is expressed in the following formula:

a=\frac{V_{f}-V_{o}}{t}

Where:

V_{f}=610 m/s is the final velocity of the projectile

V_{o}=0 m/s  is the initial velocity of the projectile

t=0.6 s is the time

Solving:

a=\frac{610 m/s-0 m/s}{0.6 s}

a=1016.66 m/s^{2} This is the acceleration of the projectile

6 0
3 years ago
How did people studying lunar eclipses learn that Earth is round?
qwelly [4]

Answer:

Scientists have studied eclipses since ancient times. Aristotle observed that the Earth's shadow has a circular shape as it moves across the moon. He posited that this must mean the Earth was round. Another Greek astronomer named Aristarchus used a lunar eclipse to estimate the distance of the Moon and Sun from Earth

4 0
3 years ago
Read 2 more answers
The Capacitive reactance of a 0.094uF capacitor when a frequency of 25kHz is applied is lus 68 Ohms 0.68 Ohms luf
Nana76 [90]

Answer:

Capacitive reactance of the capacitor is 68 ohms

Explanation:

It is given that,

Capacitance, C=0.094\ \mu F=0.094\times 10^{-6}\ F

Frequency, f=25\ kHz=25\times 10^3\ Hz

Capacitive reactance is given by :

X_C=\dfrac{1}{2\pi fC}

X_C=\dfrac{1}{2\pi 25\times 10^3\times 0.094\times 10^{-6}}

X_C=67.72\ \Omega

or

X_C=68\ \Omega

So, the capacitive reactance of the capacitor is 68 ohms. Hence, this is the required solution.

8 0
3 years ago
If you have two uncertainties, and they are from two different sources and contribute to the uncertainty of a measurement, what
Darya [45]

The propagation errors we can find the uncertainty of a given magnitude is the sum of the uncertainties of each magnitude.

                           Δm = ∑  | \frac{dm}{dx_i} | \ \Delta x_i

Physical quantities are precise values ​​of a variable, but all measurements have an uncertainty, in the case of direct measurements the uncertainty is equal to the precision of the given instrument.

When you have derived variables, that is, when measurements are made with different instruments, each with a different uncertainty, the way to find the uncertainty or error is used the propagation errors to use the variation of each parameter, keeping the others constant and taking the worst of the  cases, all the errors add up.

If m is the calculated quantity, x_i the measured values ​​and Δx_i the uncertainty of each value, the total uncertainty is

                      Δm = ∑  | \frac{dm}{dx_i } | \ \Delta x_i    | dm / dx_i | Dx_i

               

for instance:

If the magnitude is  a average of two magnitudes measured each with a different error

                     m = \frac{m_1+m_2}{2}

                     Δm = | \frac{dm}{dx_1} |  Δx₁ + | \frac{dm}{dx_2} | Δx₂

                     \frac{dm}{dx_1} = ½

                     \frac{dm}{dx_2} = ½

                     Δm = \frac{1}{2} Δx₁ + ½ Δx₂

                     Δm = Δx₁ + Δx₂

In conclusion, using the propagation errors we can find the uncertainty of a given quantity is the sum of the uncertainties of each measured quantity.

Learn more about propagation errors here:

brainly.com/question/17175455

6 0
3 years ago
The microwaves in a certain microwave oven have a wavelength of 12.2 cm. How wide must this oven be so that it will contain five
leva [86]

Answer:

a

 l = 0.305 \  m

b

  f = 3.0*10^{11} \  Hz

Explanation:

From the question we are told that

  The  wavelength is  \lambda  =  12.2 \  cm  = 0.122 \  m

  The  number of antinodal planes of the electric field considered is n  =  5

The  width is mathematically represented as

       l  =  \frac{ n \lambda}{2}

       l = \frac{5 * 0.122 }{ 2}

      l = 0.305 \  m

Generally the  frequency the errors was made is  mathematically represented as

   f =  \frac{c}{\lamda_k}

Here c is the speed of light with value  c =  3.0*10^{8} \  m/s

     \lambda_k is the wavelength of the microwave has to be in order for there still to be five antinodal planes of the electric field along the width of the oven, which is mathematically represented as

     \lambda_k  =  \frac{ \lambda *  \frac{0.04}{2} }{n/2}

      \lambda_k  =  \frac{0.122*0.02}{5/2}

So

   f =  \frac{3.0*10^{8}}{0.000976}

    f = 3.0*10^{11} \  Hz

   

       

8 0
3 years ago
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