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Pani-rosa [81]
3 years ago
8

A rocket rises vertically, from rest, with an acceleration of 3.2 m/s2 until it runs out of fuel at an altitude of 1300 m. After

this point, its acceleration is that of gravity, downward. (a) What is the velocity of the rocket when it runs out of fuel? (Assume up is positive.)
(b) How long does it take to reach this point?
(c) What maximum altitude does the rocket reach?
(d) How much time (total) does it take to reach maximum altitude?
(e) With what velocity does the rocket strike the Earth? (Assume up is positive.)
(f) How long (total) is it in the air?

Physics
1 answer:
svetlana [45]3 years ago
6 0

Explanation:

Below is an attachment containing the solution.

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Answer:

B) False.

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The correct option is C) The angle between the vectors is 120°.

Why?

We can solve the problem and find the correct option using the Law of Cosine.

Let A and B, the given two sides and R the resultant (sum),

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So, using the law of cosines, we have:

R^{2}=A^{2}+B^{2}+2ABCos(\alpha)\\ \\A^{2}=A^{2}+A^{2}+2*A*A*Cos(\alpha)\\\\0=A^{2}+2*A^{2}*Cos(\alpha)\\\\Cos(\alpha)=-\frac{A^{2}}{2*A^{2}}=-\frac{1}{2}\\\\\alpha =Cos(-\frac{1}{2})^{-1}=120\°

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Have a nice day!

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