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Pani-rosa [81]
4 years ago
8

A rocket rises vertically, from rest, with an acceleration of 3.2 m/s2 until it runs out of fuel at an altitude of 1300 m. After

this point, its acceleration is that of gravity, downward. (a) What is the velocity of the rocket when it runs out of fuel? (Assume up is positive.)
(b) How long does it take to reach this point?
(c) What maximum altitude does the rocket reach?
(d) How much time (total) does it take to reach maximum altitude?
(e) With what velocity does the rocket strike the Earth? (Assume up is positive.)
(f) How long (total) is it in the air?

Physics
1 answer:
svetlana [45]4 years ago
6 0

Explanation:

Below is an attachment containing the solution.

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Why law of floatation is called the special condition of Archimedes principle​
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The mysterious visitor that appears in the enchanting story The Little Prince was said to come from a planet that "was scarcely
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Answer:

Part a)

g = 1 \times 10^{-5} m/s^2

Part b)

v = 0.011 m/s

Explanation:

Part a)

As we know that the acceleration due to gravity is given as

g = \frac{GM}{R^2}

g = \frac{G(\frac{4}{3}\pi R^3 \rho)}{R^2}

g = \frac{4}{3}\pi \rho G R

now we know that

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Part b)

As we know that the escape speed is given as

v = \sqrt{\frac{2GM}{R}}

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v = 0.011 m/s

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