Question 7 of 10

Kepler's____ of planetary motion states that the planets have an elliptical orbit, with the Sun at one focal point of the ellips

Evgen [1.6K]

Kepler's laws were enunciated to model in a mathematical way the movement of the planets in their respective orbits around the Sun.

There are three laws of Kepler.

In particular, Kepler's first law states the following:

"All the planets move around the Sun describing elliptical orbits, the Sun is in one of the foci of the ellipse."

Answer:

Kepler's 1st law of planetary motion states that the planets have an elliptical orbit, with the Sun at one focal point of the ellipse.

a. 1st law

8 0

3 years ago

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A 12.0-g bullet is fi red horizontally into a 100-g wooden block initially at rest on a horizontal surface. After impact, the bl

allochka39001 [22]

Answer:

$v_1 = 91.3 m/s$

Explanation:

By energy conservation and work energy theorem we can say that after bullet hits the block, it will move on the rough floor and comes to rest

so here work done by frictional force = change in kinetic energy

so we know that

$W_f = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2$

$-\mu mg d = \frac{1}{2}m(v_f^2 - v_i^2)$

$-0.650(9.81)(7.5) = \frac{1}{2}(0 - v_i^2)$

$47.8 = \frac{1}{2}v^2$

$v = 9.78 m/s$

now by momentum conservation we have

$m_1 v_1 = (m_1 + m_2) v$

$12 v_1 = (100 + 12) 9.78$

$v_1 = 91.3 m/s$

3 0

2 years ago

A truck driver sees a dog running into the road. He immediately brakes. Describe the energy transfers in the truck as it comes t

Eduardwww [97]

Answer: find the answer in the explanation as kinetic energy converts to potential energy.

Explanation:

Before the truck driver sees a dog running into the road, The mechanical energy state of the truck will be kinetic energy at maximum.

Immediately he applied the brakes, the mechanical energy of the truck will be combination of kinetic energy and potential energy.

The kinetic energy will gradually decrease as potential energy continue to increase till it reaches maximum potential energy.

The truck will come to a stop at maximum potential energy

3 0

3 years ago

Two moles of an ideal monatomic gas go through the cycle abc. For the complete cycle, 800 J of heat flows out of the gas. Proces

KiRa [710]

a) Sketches of all possible pv-diagrams for the cycle are attached below

b) The work W $_{ac}$ for the process Ca is : 2462.8 J

Given data :

Amount of heat flowing out = 800 J

Ta = 200 K

Tb = 300 K

R = 800

B) Determine the work W for the process Ca

Wₐs = -pdv

= - [ pVb - pVa ] ---- ( 1 )

note : pVb = nRTb , pVa = nRTa

Equation ( 1 ) becomes

= -nR [ Tb - Ta ]

= - 2(8.314 ) [ 300 - 200 ]

= - 1662.87

given that W $_{bs}$ = 0 which is isochonic

dv = 0 ( cyclic process ) = d∅ - dw

∴ 0 = 800 - ( Wₐs + W $_{ac}$ )

Therefore : W $_{ac}$ = 800 + 1662.8 = 2462.8 J

Hence we can conclude that the work W for the process Ca = 2462.8 J

Learn more about Pv diagrams : brainly.com/question/25401637

Download pdf

3 0

2 years ago

Pleaseee helpppp meeeeeee I will give pountsss

MrRa [10]

Answer:

m= 0. 113 kg

W = 1.1074 N

g = 9.8 m/ s²

m= 870 kg

W = 8526 N

g = 9.8 m/s²

a) weight on earth:

weight = mass × acceleration due to gravity (g)

g on earth = 9.8 m/s²

W = 75 × 9.8

W = 735 N

b) g on Mars

285 = 75 × g

g = 285/ 75

g = 3.8 m/ s²

3 0

2 years ago