Question 7 of 10

Two objects, one with a mass of 2 m and one with a mass of 4 m are attracted to each other

Nadusha1986 [10]

It would be 7 M 4 m x 2 m equals 8 M - 1 =7

3 0

2 years ago

A cosmic-ray proton in interstellar space has an energy of 10.0 MeV and executes a circular orbit having a radius equal to that

kherson [118]

Answer:

= 7.88 × 10^-12 T

Explanation:

From the above question, we are told that:

Kinetic Energy of the proton is K. E = 10.0 MeV

Step 1

We convert 10.0 MeV to Joules

1 Mev = 1.602 × 10-13 Joules

10.0 MeV = 10.0 × 1.602 × 10^-13 Joules = 1.602 × 10^-12 J

Hence, the Kinectic energy of a proton = 1.602 × 10^-12 J

Step 2

Find the Speed of the Proton

The formula for Kinectic Energy =

K.E = 1/ 2 mv²

Where

m = mass of the proton

v = speed of the proton

K.E of the proton = 1.602 × 10^-12 J

Mass of the proton = 1.6726219 × 10^-27 kilograms

Speed of the proton = ?

1.602 × 10^-12J = 1/2 × 1.6726219 × 10^-27 × v²

1.602 × 10^-12J = 8.3631095 ×10^-28 × v²

v² = 1.602 × 10^-12/8.3631095 ×10^-28

v = √(1.602 × 10^-12/8.3631095 ×10^-28)

v = 43772331.227m/s

v = 4.3772331227 × 10^7m/s

Approximately = 4.4 × 10^7 m/s

Step 3

Find the Magnetic Field of that region of space

The formula for Magnetic Field =

B = m v / q r

We are told that the proton executes a circular orbit, hence,

mv = √2m(KE)

m = Mass of the proton = 1.6726219 × 10^-27 kg

K.E of the proton = 1.602 × 10^-12 J

v = speed of the proton = 4.4 × 10^7 m/s

q = Electric charge = 1.6 × 10^-19 C

r = radius of the orbit = 5.80Ã10^10 m

= 5.8 × 10^10m

Magnetic Field =

=√ (2 × 1.6726219 × 10^-27 kg × 1.602 × 10^-12 J) /( 1.6 × 10^-19 C × 5.80 × 10^10 m)

= 7.88 × 10^-12 T

The magnetic field in that region of space is approximately 7.88 × 10^-12 T

4 0

2 years ago

Describe a situation where you can be traveling at a low speed but have an extremely high velocity

Reil [10]

Answer:

Cruising at 35,000 feet in an airliner, straight toward the east,

at 500 miles per hour

Explanation:

3 0

2 years ago

Read 2 more answers

Please help me asap

ddd [48]

Answer:

if I aint wrong it would 2nd one

8 0

2 years ago

a conducting rod whose length is 25 cm is placed on a u-shaped metal wire that has a resistance of 8.0 ω . the wire and the rod

andreyandreev [35.5K]

Answer:

The current is $I = 1 A$

The direction is anti-clockwise

Explanation:

The diagram for this question is shown on the first uploaded image

From the question we are told that

the length of the conducting rod is $L = 25 \ cm = \frac{25}{100} = 2.5 \ m$

The resistance is $R = 8 \Omega$

The magnetic field is $B = 0.40\ T$

The speed of the rod is $v = 6.0 m/s$

The emf induced is

$\epsilon = BLv$

substituting values we have

$\epsilon = 0.40 * 2.5 * 8$

$\epsilon = 8V$

From ohm law the induced current would be

$I = \frac{\epsilon}{R }$

substituting values we have

$I = \frac{8}{8 }$

$I = 1 A$

The direction anticlockwise this because according to lenze law the current due to change in magnetic field will act in the opposite direction of the force causing the magnetic field to change

4 0

3 years ago