P=I^2 *R
600 =5.0^2 *R
R=24
Answer: 24 ohms
I hope it’s correcttttttt...
Inertia is the force in play here
Given:
P1 = 400 kPa
T1 = 110 K
T2 = 235K
Required:
P2
Solution:
Apply Gay-Lussac’s
law where P/T = constant
P1/T1 = P2/T2
P2 = T2P1/T1
P2 = (235K)(400kPa)
/ (110K)
P2 = 855 kPa
If we ignore air resistance, as we always do,
there is no horizontal acceleration.
Gravity acts only in the vertical direction, and
no other forces act on the ball after the punt.
