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gogolik [260]
2 years ago
11

Critical reasoning: We also use simulation to understand how the software would behave in the event of potential collisions. Giv

en the following scenario, what variables would you manipulate to try and make a collision occur? Say for example, the self-driving car is approaching an intersection with a yellow light for their direction of travel, there is also a car on the road following closely behind it in the same direction, in the same lane. The two cars come to a stop without incident in this example. What variables would you manipulate in simulation to cause a collision?
Physics
1 answer:
jeka942 years ago
6 0

Using kinematic reasoning, the answers for the changes that can cause crashes are:

we can manipulate

  • The speed of the vehicles, especially that of the second car
  • he traffic light change time
  • Change some condition of the pavement after the first vehicle passes

Autonomous systems are systems that take a series of signals from the outside, analyze them and carry out actions according to how to handle them.

In that case you have two cars one behind the other at a short distance a traffic light with a yellow light is approaching.

Some parameters can be modified to cause the crash:

  • The car in front accelerates to pass the traffic light, but the traffic light changed to red, in this case if the car behind also accelerated, there may not be enough distance to stop and crash.

  • You can change the traffic light to green whereby the first car continues its speed, but the traffic light time changes very quickly to red, whereby the first car stops, but the car behind cannot stop.

  • The car behind accelerates to also pass the yellow light, but turns red and the first one crashes to a stop.

  • We change some condition of the pavement after the first vehicle passes, for example wetting the pavement, which decreases the coefficient of friction, consequently the second vehicle does not have time to stop.

We can appreciate that if there is not a good and fast communication between the two vehicles, it is easy for them to crash.

In conclusion, using kinematic reasoning, the answers for the changes that can test shocks are found:

  • The second vehicle increases speed and the first must brake sharply

Learn more about stopping distance here:

brainly.com/question/24254597

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laiz [17]

Answer:

law of conservation of energy is that a perpetual motion machine of the first kind cannot exist, that is to say, no system without an external energy supply can deliver an unlimited amount of energy to its surroundings

Explanation:

Hope it helps.

Mark me as Brainliest plz!

3 0
2 years ago
In which labeled portion of the curve would you use the heat of vaporization to calculate the heat absorbed? (image attached ins
sergij07 [2.7K]
<span>In the labeled portion of the curve ,you use the heat of vaporization to calculate the heat absorbed in the 4th portion. It is indicated in the picture that it is the region where vaporization occurs, that is why you need to consider this portion to calculate.</span>
3 0
3 years ago
9. Consider the elbow to be flexed at 90 degrees with the forearm parallel to the ground and the upper arm perpendicular to the
mojhsa [17]

Answer:

Moment about SHOULDER  ∑ τ = 3.17 N / m,

Moment respect to ELBOW   Στ= 2.80 N m

Explanation:

For this exercise we can use Newton's second law relationships for rotational motion

         ∑ τ = I α

   

The moment is requested on the elbow and shoulder at the initial instant, just when the movement begins.

They indicate the angular acceleration, for which we must look for the moments of inertia of the elements involved

The mass of the forearm with the included weight is approximately 2.3 kg, with a length of about 50cm

Moment about SHOULDER

          ∑ τ = I α

           I = I_forearm + I_sphere

the forearm can be approximated as a fixed bar at one end

            I_forearm = ⅓ m L²

the moment of inertia of the mass in the hand, let's approach as punctual

            I_mass = m L²

we substitute

           ∑ τ = (⅓ m L² + M L²) α

let's calculate

          ∑ τ = (⅓ 2.3 0.5² + 0.5 0.5²) 10

           ∑ τ = 3.17 N / m

Moment with respect to ELBOW

In this case, the arm exerts an upward force (muscle) that is about 3 cm from the elbow

         Στ = I α

         I = I_ forearm + I_mass

         I = ⅓ m (L-0.03)² + M (L-0.03)²

         

let's calculate

        i = ⅓ 2.3 0.47² + 0.5 0.47²

        I = 0.2798 Kg m²

        Στ = 0.2798 10

        Στ= 2.80 N m

3 0
3 years ago
PLEASE HELP ME WITH THIS ONE QUESTION
Marizza181 [45]

Answer:

c) 2.02 x 10^16 nuclei

Explanation:

The isotope decay of an atom follows the equation:

ln[A] = -kt + ln[A]₀

<em>Where [A] is the amount of the isotope after time t, k is decay constant, [A]₀ is the initial amount of the isotope</em>

[A] = Our incognite

k is constant decay:

k = ln 2 / Half-life

k = ln 2 / 4.96 x 10^3 s

k = 1.40x10⁻⁴s⁻¹

t is time = 1.98 x 10^4 s

[A]₀ = 3.21 x 10^17 nuclei

ln[A] = -1.40x10⁻⁴s⁻¹*1.98 x 10^4 s + ln[3.21 x 10^17 nuclei]

ln[A] = 37.538

[A] = 2.01x10¹⁶ nuclei remain ≈

<h3>c) 2.02 x 10^16 nuclei</h3>
7 0
2 years ago
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vlada-n [284]
You need to provide a picture or tell us the examples... we can’t see what you see
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