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gogolik [260]
2 years ago
11

Critical reasoning: We also use simulation to understand how the software would behave in the event of potential collisions. Giv

en the following scenario, what variables would you manipulate to try and make a collision occur? Say for example, the self-driving car is approaching an intersection with a yellow light for their direction of travel, there is also a car on the road following closely behind it in the same direction, in the same lane. The two cars come to a stop without incident in this example. What variables would you manipulate in simulation to cause a collision?
Physics
1 answer:
jeka942 years ago
6 0

Using kinematic reasoning, the answers for the changes that can cause crashes are:

we can manipulate

  • The speed of the vehicles, especially that of the second car
  • he traffic light change time
  • Change some condition of the pavement after the first vehicle passes

Autonomous systems are systems that take a series of signals from the outside, analyze them and carry out actions according to how to handle them.

In that case you have two cars one behind the other at a short distance a traffic light with a yellow light is approaching.

Some parameters can be modified to cause the crash:

  • The car in front accelerates to pass the traffic light, but the traffic light changed to red, in this case if the car behind also accelerated, there may not be enough distance to stop and crash.

  • You can change the traffic light to green whereby the first car continues its speed, but the traffic light time changes very quickly to red, whereby the first car stops, but the car behind cannot stop.

  • The car behind accelerates to also pass the yellow light, but turns red and the first one crashes to a stop.

  • We change some condition of the pavement after the first vehicle passes, for example wetting the pavement, which decreases the coefficient of friction, consequently the second vehicle does not have time to stop.

We can appreciate that if there is not a good and fast communication between the two vehicles, it is easy for them to crash.

In conclusion, using kinematic reasoning, the answers for the changes that can test shocks are found:

  • The second vehicle increases speed and the first must brake sharply

Learn more about stopping distance here:

brainly.com/question/24254597

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Answer:

Conservation of momentum.

Momentum is zero after collision, no direction or speed.

Explanation:

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Determine the acceleration that result when a 12-N net force is applied to a 3-kg object and then to a 6-kg object
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For 3 kg mass: <em>F = \lpha ma,a = \frac{F}{m} = \frac{12N}{3kg} = 4\lpha m / s^{2}</em>

For 6 kg mass: <em>F = \lpha ma,a = \frac{F}{m} = \frac{12N}{6kg} = 2\lpha m / s^{2}</em>


Hope this helped, have a great day!~

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Why is the force of gravity on your body weaker on the Moon than on the Earth?
andrezito [222]

Answer:

The moon’s gravity is weaker than the earth gravity due to the smaller in size as compared to the earth. As there is no atmosphere present on the moon gravity, so there are fewer chances of withstanding temperature.

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3 years ago
Se o Universo tem uma idade definida, de aproximadamente 13,7 bilhões de anos, o que existiu antes do big-bang?
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3 years ago
Un automovil parte del reposo y acelera uniformemente hasta alcanzar una rapidez de 0,255km/h en un tiempo de 3/4 Minutos determ
Elden [556K]

Answer:

a = 1.5*10^-3 m/s^2

x = 0.033m = 3.3cm

Explanation:

To calculate the acceleration and the distance traveled by the car you use the following formulas:

v=v_o+at    (1)

x=v_ot+\frac{1}{2}at^2   (2)

v: final velocity = 0,255 km/h

vo: initial velocity = 0 m/s

t: time = 3/4 min

a: acceleration = ?

x: distance

In order to use the equations (1) and (2) you first convert the units of the final velocity to m/s, and the time to seconds.

v=0,255\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}\\\\v=0.07m/s\\\\t=\frac{3}{4}min*\frac{60s}{1min}=45s

Next, you solve the equation (1) for the acceleration a:

a=\frac{v}{t}=\frac{0.07m/s}{45s}=1.5*10^{-3}\frac{m}{s^2}

With this value of a you can calculate the distance traveled by the car, by using the equation (2):

x=\frac{1}{2}(1.5*10^{-3}m/s^2)(45s)^2=0.033m=3.3cm

hence, the acceleration of the car is 1.5*10^-3 m/s^2 and the distance traveled in 3/4 min is 0.033m

5 0
3 years ago
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