How many elements are artificially made?

When water vapor changes to a liquid what is it called

Mademuasel [1]

Answer:

$hello \: your \: answer \: is \: here.$

Explanation:

<h2>Condensation is the change of water from its gaseous form (water vapor) into liquid water. Condensation generally occurs in the atmosphere when warm air rises, cools and looses its capacity to hold water vapor. As a result, excess water vapor condenses to form cloud droplets.</h2>

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5 0

3 years ago

What forms the structure called a coral reef

lina2011 [118]

When the little fish die they sink to the bottom, and after time the skeletons build up on top of each other.

7 0

3 years ago

Read 2 more answers

Is aluminum foil a mixture or a pure substance?

Naddik [55]

Pure Substance.........

6 0

3 years ago

James was standing on a boat in deep ocean water. He wanted to see how long it would take a tennis ball to reach the shore if he

Black_prince [1.1K]

Answer:

only the wave energy of the water moves

Explanation:

The plan will not work due to the fact that only the wave energy of the water moves and not the water itself.

The wave motion of water does not displace the water. It is only able to transfer energy from one point to another within the medium. Hence, the ball will hardly be displaced because the water itself does not move. However, it can get to the shore with the assistance of the water current.

7 0

3 years ago

A compound contains 1.2 g of carbon, 3.2 g of oxygen and 0.2g of hydrogen. Find the formula of the compound

Karolina [17]

Answer:

The empirical formula of the compound is $C_{0.504}HO_{1.008}$ .

Explanation:

We need to determine the empirical formula in its simplest form, where hydrogen ( $H$ ) is scaled up to a mole, since it has the molar mass, and both carbon ( $C$ ) and oxygen ( $O$ ) are also scaled up in the same magnitude. The empirical formula is of the form:

$C_{x}HO_{y}$

Where $x$ , $y$ are the number of moles of the carbon and oxygen, respectively.

The scale factor ( $r$ ), no unit, is calculated by the following formula:

$r = \frac{M_{H}}{m_{H}}$ (1)

Where:

$m_{H}$ - Mass of hydrogen, in grams.

$M_{H}$ - Molar mass of hydrogen, in grams per mole.

If we know that $M_{H} = 1.008\,\frac{g}{mol}$ and $m_{H} = 0.2\,g$ , then the scale factor is:

$r = \frac{1.008}{0.2}$

$r = 5.04$

The molar masses of carbon ( $M_{C}$ ) and oxygen ( $M_{O}$ ) are $12.011\,\frac{g}{mol}$ and $15.999\,\frac{g}{mol}$ , then, the respective numbers of moles are: ( $r = 5.04$ , $m_{C} = 1.2\,g$ , $m_{O} = 3.2\,g$ )