Answer:
0.0693M Fe
Explanation:
It is possible to quantify Fe in a sample using Mn as internal standard using response factor formula:
F = A(analyte)×C(std) / A(std)×C(analyte) <em>(1)</em>
Where A is area of analyte and std, and C is concentration.
Replacing with first values:
F = 1.05×2.00mg/mL / 1.00×2.50mg/mL
<em>F = 0.84</em>
In the unknown solution, concentration of Mn is:
13.5mg/mL × (1.00mL/6.00mL) = <em>2.25 mg Mn/mL</em>
Replacing in (1) with absorbances values and F value:
0.84 = 0.185×2.25mg/mL / 0.128×C(analyte)
C(analyte) = <em>3.87 mg Fe / mL</em>
As molarity is moles of solute (Fe) per liter of solution:
= <em>0.0693M Fe</em>
10.9 because of mass= moles/mv it’s just basic chemistry
30ml of a 2.50 M hydrochloric acid solution is required to make 100.0 mL of a 0.750 M solution.
<h3>What is HCl?</h3>
HCl is an acid which is made up of hydrogen and chlorine gas.
By the formula of dilution
M1V1 = M2V2
where V1 = 2.50 m
M2 = 100.0
V2 = 0.750 m
M1 × 2.50 m = 100.0 × 0.750 m
M1 = 30 ml
Thus, the M1 is 30 ml option a is correct.
Learn more about HCl
brainly.com/question/3637432
The ksp value for calcium hydroxide at this temperature is 5.20 × 10⁻⁶.
<h3>What is ksp?</h3>
Ksp is an equilibrium constant of a solid substance dissolved in a liquid solution.
Given that, the volume of water is 0.178 l, 0.264 g of Ca(OH)² dissolves in enough water
The solution equilibrium is
Ca(OH)² = Ca + 2OH
The molar solubility is
0.186 / 74.00 / 0.230 = 0.0109 M
The ksp value will be
Ksp = (s) (2S)²
Putting the values in the formula
(0.0109) x (2 x 0.0109)² = 5.20 × 10⁻⁶.
Thus, the ksp value for calcium hydroxide is 5.20 × 10⁻⁶.
To learn more about ksp value, refer to the link:
brainly.com/question/27132799
#SPJ4
