1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
djverab [1.8K]
4 years ago
5

23. Using the periodic table, what is the oxidation number of:

Chemistry
1 answer:
Aloiza [94]4 years ago
8 0

Answer:

a. +2

b. +3

c. -1

Explanation:

The typical oxidation states can be determined from the periodic table based on the number of valence electrons an atom has.

a. Calcium belongs to group 2A, meaning it has 2 valence electrons and, therefore, would have an oxidation state of +2 in compounds.

b. Aluminum is in group 3A, meaning it has 3 valence electrons and would have an oxidation state of +3 in compounds when the 3 electrons are lost.

c. Fluorine would become fluorine if it gained 1 additional electron to achieve an octet, so its oxidation state would be -1.

You might be interested in
The modern periodic table is arranged by increasing
Lilit [14]

The periodic table of elements arranges all of the known chemical elements in an informative array. Elements are arranged from left to right and top to bottom in order of increasing atomic number. Order generally coincides with increasing atomic mass. The rows are called periods.

5 0
4 years ago
Describe how you would prepare approximately 2 l of 0.050 0 m boric acid, b(oh)3.
Elenna [48]

The given concentration of boric acid = 0.0500 M

Required volume of the solution = 2 L

Molarity is the moles of solute present per liter solution. So 0.0500 M boric acid has 0.0500 mol boric acid present in 1 L solution.

Calculating the moles of 0.0500 M boric acid present in 2 L solution:

2 L * \frac{0.0500 mol B(OH)_{3} }{1 L} = 0.100 mol B(OH)_{3}

Converting moles of boric acid to mass:

0.100 mol B(OH)_{3} * \frac{61.83 g}{mol B(OH)_{3}}   = 6.183 g

Therefore, 6.183 g boric acid when dissolved and made up to 2 L with distilled water gives 0.0500 M solution.


5 0
4 years ago
In which of the following pure substances would hydrogen bonding be expected?
Novay_Z [31]

Answer:propanoic acid

Explanation:

Carboxylic acids contain the COOH group. This group is capable of hydrogen bonding leading to association of the molecules. Cyclobutane is a cyclic alkane and acetone is a ketone. Non of these compounds posses a polar -OH bond which is necessary for the occurrence of hydrogen bond. Hydrogen bonds only occur in carboxylic acids and alcohols. Hydrogen bond leads to molecular association and high boiling points.

5 0
4 years ago
Read 2 more answers
Please help me with this chem question!!
schepotkina [342]

Answer:

caca123

Explanation:

UM

6 0
3 years ago
Deanna stirred a teaspoon of sugar into a glass of warm water. The sugar completely dissolved in the water. Check any statement
Sergeeva-Olga [200]

Answer:

D

Explanation:

From my experience this is what happens when I put sugar in warm water glass

4 0
3 years ago
Read 2 more answers
Other questions:
  • Which sample contains the most concentrated solution of hydrochloric acid (HCl)?
    12·1 answer
  • Mn2(CO3)3 what is the cation and anion in this compound?
    9·2 answers
  • When hydrocarbons are burned in a limited amount of air, both CO and CO2 form. When 0.430 g of a particular hydrocarbon was burn
    15·1 answer
  • What is the best Dog Training Organization for German Shepherds
    11·2 answers
  • 25.0 mL of a 3.25 M solution is diluted to 450.0 mL. What is the concentration of the diluted solution?
    10·1 answer
  • What is the mass (in grams) of 4.5 x 10^23 units of NaCl?<br><br> could you also explain?
    9·1 answer
  • Balance the Following C₇H₁₆ + O₂ ---&gt; CO₂ + H₂0
    15·1 answer
  • Help me please I really need help on this?
    5·1 answer
  • 5. What is a habitat?
    10·2 answers
  • Identify the reactants in the equation: 6C0, + 6H2O - CHUO+ 60,
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!