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djverab [1.8K]
4 years ago
5

23. Using the periodic table, what is the oxidation number of:

Chemistry
1 answer:
Aloiza [94]4 years ago
8 0

Answer:

a. +2

b. +3

c. -1

Explanation:

The typical oxidation states can be determined from the periodic table based on the number of valence electrons an atom has.

a. Calcium belongs to group 2A, meaning it has 2 valence electrons and, therefore, would have an oxidation state of +2 in compounds.

b. Aluminum is in group 3A, meaning it has 3 valence electrons and would have an oxidation state of +3 in compounds when the 3 electrons are lost.

c. Fluorine would become fluorine if it gained 1 additional electron to achieve an octet, so its oxidation state would be -1.

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If a naturally occurring sample of an unidentified element is found to contain three isotopes (A, B, and C) and consists of 90.5
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If a naturally occurring sample of an unidentified element is found to contain three isotopes (A, B, and C) and consists of 90.5% isotope A (mass number 20), 0.3% isotope B (mass number 21), and 9.3% isotope C (mass number 22), the atomic weight of the element measured from the sample will be greater than 21 amu.

To calculate the average atomic mass, multiply the fraction through the mass number for every isotope, then add them together. Whenever we do mass calculations concerning elements or compounds (combos of elements), we usually use average atomic loads.

For instance, carbon-14 is a radioactive isotope of carbon that has six protons and 8 neutrons in its nucleus. We name it carbon-14 because the overall range of protons and neutrons within the nucleus also called the mass number, provides up to fourteen (6+8=14).

Together, the quantity of protons and the range of neutrons determine an detail's mass variety. Due to the fact, that an element's isotopes have barely unique mass numbers, the atomic mass is calculated by obtaining the suggested mass numbers for its isotopes.

Learn more about atomic mass here brainly.com/question/1358482

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2 years ago
If you had only one match and entered a dark room containing an oil lamp, some newspaper, and some kindling wood, which would yo
lana [24]
Hahahaha the oil lamp~
4 0
3 years ago
What is the best reason for the difference in properties of LiCl and C6H14O?
Artist 52 [7]

Answer: Difference in properties of these two compounds are because one compound is covalent and the other one is ionic.

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C_6H_{14}O is a organic compound formed by the sharing of electrons between the elements, hence is termed as a covalent compound.

Hence, the properties are different because one of the compound is covalent and other is ionic.

4 0
3 years ago
Read 2 more answers
PLEASE HELP 100 POINTS
bonufazy [111]

Answer:

Gaseous nitrogen (78% in air) is fixed (by nitrogen fixing bacteria, and during lightning), then absorbed and assimilated by plants in the form of proteins, as well as nucleic acids. ... Nitrogen is returned to soil with excretory materials of animals and dead organisms.

Explanation:

Nitrates (or nitrites) are natural chemicals that are found in the soil, air and water. Nitrates are also used as a food additive to stop the growth of bacteria and to enhance the flavor and color of foodsAmmonium is also a general name for positively charged or protonated substituted amines and quaternary ammonium cations (NR + 4. ), where one or more hydrogen atoms are replaced by organic groups (indicated by R).an obsessive interest in or feeling about someone or something.

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Denitrification: the loss or removal of nitrogen or nitrogen compounds specifically : reduction of nitrates or nitrites commonly by bacteria (as in soil) that usually results in the escape of nitrogen into the air

3 0
3 years ago
The value of ka for nitrous acid (hno2) at 25 ∘c is 4.5×10−4. what is the value of δg at 25 ∘c when [h+] = 5.9×10−2m , [no2-] =
LuckyWell [14K]
To get the value of ΔG we need to get first the value of ΔG°:

when ΔG° = - R*T*㏑K

when R is constant in KJ = 0.00831 KJ

T is the temperature in Kelvin = 25+273 = 298 K

and K is the equilibrium constant = 4.5 x 10^-4

so by substitution:

∴ ΔG° = - 0.00831 * 298 K * ㏑4.5 x 10^-4

        = -19 KJ

then, we can now get the value of ΔG when:

ΔG = ΔG° - RT*㏑[HNO2]/[H+][NO2]

when ΔG° = -19 KJ

and R is constant in KJ = 0.00831 

and T is the temperature in Kelvin = 298 K

and [HNO2] = 0.21 m & [H+] = 5.9 x 10^-2 & [NO2-] = 6.3 x 10^-4 m  

so, by substitution:

ΔG = -19 KJ - 0.00831 * 298K* ㏑(0.21/5.9x10^-2*6.3 x10^-4 )

       = -40

     
8 0
3 years ago
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