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sasho [114]
3 years ago
9

Which of the following statements are true? Check all that apply. Atoms with the same atomic number have the same number of elec

trons Atoms with the same atomic number have the same number of neutrons Atoms with the same atomic number can have different numbers of electrons Atoms with the same number can have different numbers of neutrons
Physics
1 answer:
malfutka [58]3 years ago
5 0

Answer:

Two correct answers (the first one and the last one listed):

<em>Atoms with the same atomic number have the same number of electrons. </em>

<em>Atoms with the same atomic number can have different numbers of neutrons.</em><em> </em>

Explanation:

There are two correct answers:

<em>Atoms with the same atomic number have the same number of electrons. </em>This is because neutral atoms have the same number of electrons than of protons in the nuclei. And the number of protons in the nucleus characterize the particular element and is called the "Atomic number."

and

<em>Atoms with the same atomic number can have different numbers of neutrons.</em><em> </em>These constitute the isotopes of the element characterized by the given atomic number.

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Naddik [55]

Answer:

The velocity of the boat 15 seconds later is 5.6 meters per second.

Explanation:

We assume that sailboat can be modelled as particle, so that we use solely translations equations. It is noticed that the sailboat is move by action of the wind and drag force of the water is opposed to such force, but the last force has a greater magnitude than the first one, meaning that net force is less than zero.

From Newton's Laws we have the following equation of equilibrium for the sailboat:

\Sigma F = F - f = m\cdot a (Eq. 1)

Where:

F - Force from the wind exerted on the sailboat, measured in newtons.

f - Drag force of the water, measured in newtons.

m - Mass of the sailboat, measured in kilograms.

a - Net acceleration of the sailboat, measured in meters per square second.

If we know that F = 3.90\times 10^{3}\,N, f = 4.35\times 10^{3}\,N and m = 1250\,kg, then the net acceleration of the sailboat is:

a = \frac{F-f}{m}

a = \frac{3.90\times 10^{3}\,N-4.35\times 10^{3}\,N}{1250\,kg}

a = -\frac{9}{25}\,\frac{m}{s^{2}}

If sailboat decelerates uniformly, then we can get the final velocity of the boat by using this equation of motion:

v = v_{o}+a\cdot t (Eq. 2)

Where:

v_{o}, v - Initial and final velocities of the sailboat, measured in meters per second.

t - Time, measured in seconds.

If we get that v_{o} = 11\,\frac{m}{s}, a = -\frac{9}{25}\,\frac{m}{s^{2}} and t = 15\,s, then the final velocity of the sailboat is:

v = 11\,\frac{m}{s} +\left(-\frac{9}{25}\,\frac{m}{s^{2}}  \right)\cdot (15\,s)

v = 5.6\,\frac{m}{s}

The velocity of the boat 15 seconds later is 5.6 meters per second.

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ELEN [110]
The answer is D. Isotopes.
Hope that helped.

7 0
4 years ago
Read 2 more answers
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