<h2>
Kinetic energy just before hitting the floor is 324.57 J</h2>
Explanation:
Weight of volleyball player = 650 N
That is
Mass x Acceleration due to gravity = 650
Mass x 9.81 = 650
Mass = 66.26 kg
We also have equation of motion v² = u² + 2as
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Final velocity, v = ?
Displacement, s = 0.5 m
Substituting
v² = u² + 2as
v² = 0² + 2 x 9.81 x 0.5
v = 3.13 m/s
Velocity with which he lands on ground is 3.13 m/s
We have kinetic energy = 0.5 x Mass x Velocity²
Substituting
Kinetic energy = 0.5 x 66.26 x 3.13²
Kinetic energy = 324.57 J
Kinetic energy just before hitting the floor is 324.57 J
Answer:
24m/s²
Explanation:
Given
Distance S = 3m
Time of fall = 0.5sec
Required
Acceleration due to gravity
Using the equation of motion
S = ut+1/2gt²
Substitute the given values
3 = 0+1/2g(0.5)²
3 = 1/2(0.25)g
3 = 0.125g
g = 3/0.125
g = 24
Hence the value for the acceleration of gravity on this new planet is 24m/s²
In the given question, one important information for getting to the actual solution is not given and that is the atmospheric pressure. To find the approximate absolute pressure, it is needed to add the value of atmospheric pressure with the gage pressure.
Atmospheric pressure = 100 kPa
Then
Absolute pressure = 156 + 100 kPa
= 256 KPa.
