First question: 800J
Second question: 20.4m
Your answer should be 9.7 :)
Light travels in waves AND in bundles called "photons".
It's hard to imagine something that's a wave and also a bundle.
But it turns out that light behaves like both waves and bundles.
If you design an experiment to detect waves, then it responds to light.
And if you design an experiment to detect 'bundles' or particles, then
that one also responds to light.
Answer:
it's the second one;
if the frequency increases, wavelength decreases
Explanation:
we know, v=f×lamda(wave length)
so for constant velocity Frequency f is inversely proportional to lamda
i.e.
fα 1/lamda
so as the f increases lamda decreases and vise versa
Answer:
13 m in the + x direction.
Explanation:
Givens
m1 = m
m2 = 3m
v1= ? = x
v2 = - 3 m/s
v3 = v4 = - 1 m/s
Equation
Let x be the speed of the lighter object before collision.
Momentum before collision = momentum after collision
Solution
mx - 3m * 3m/s = (m1 + m2)*(-1)
m(x - 3*3m/s) = (m + 3m)(-1)
m(x - 9) = - 4m Cancel the ms
x - 9 = 4 Add 9 to both sides
x = 9 + 4
x = 13 m/s
