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borishaifa [10]
3 years ago
8

1. A stone is found to have a volume of 34.9 cm3. It has a mass of 30.8 g. What is the density of the stone?

Chemistry
1 answer:
zavuch27 [327]3 years ago
7 0

Answer:

<h2>Density = 0.88 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

Density  =  \frac{mass}{volume}

From the question

mass = 30.8 g

volume = 34.9 cm³

Substitute the values into the above formula and solve

That's

Density =  \frac{30.8}{34 .9}  \\  = 0.8825

We have the final answer as

<h3>Density = 0.88 g/cm³</h3>

Hope this helps you

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Two isotopes of lithium are found in nature Li6 has a mass of 6. 02u and Li7 has a mass of 7.02u . Use the atomic weight of lith
alexandr402 [8]

The isotope that is more abundant, given the data is isotope Li7

<h3>Assumption</h3>
  • Let Li6 be isotope A
  • Let Li7 be isotope B

<h3>How to determine whiche isotope is more abundant</h3>
  • Molar mass of isotope A (Li6) = 6.02 u
  • Molar mass of isotope B (Li7) = 7.02 u
  • Atomic mass of lithium = 6.94 u
  • Abundance of A = A%
  • Abundance of B = (100 - A)%

Atomic mass = [(mass of A × A%) / 100] + [(mass of B × B%) / 100]

6.94 = [(6.02 × A%) / 100] + [(7.02 × (100 - A)) / 100]

6.94 = [6.02A% / 100] + [702 - 7.02A% / 100]

6.94 = [6.02A% + 702 - 7.02A%] / 100

Cross multiply

6.02A% + 702 - 7.02A% = 6.94 × 100

6.02A% + 702 - 7.02A% = 694

Collect like terms

6.02A% - 7.02A% = 694 - 702

-A% = -8

A% = 8%

Thus,

Abundance of B = (100 - A)%

Abundance of B = (100 - 8)%

Abundance of B = 92%

SUMMARY

  • Abundance of A (Li6) = 8%
  • Abundance of B (Li7) = 92%

From the above, isotope Li7 is more abundant.

Learn more about isotope:

brainly.com/question/24311846

#SPJ1

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2 years ago
A particular substance has a measured solubility in water of 3.6g/1.0L. How much of the substance can be dissolved in 650 L of w
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I believe the correct answer is 2340g of a particular substance will be dissolved in 650 L of H2O. Hope I was helpful in some way. Thanks. Peace.
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All of the following are equal to Avogadro's number EXCEPT ____. a. the number of atoms of bromine in 1 mol Br2 b. the number of
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All the following are equal to Avogadro's number EXCEPT a. the number of atoms of bromine in 1 mol Br₂.

1 mol Br₂ contains Avogadro’s number of molecules of Br₂.

However, each molecule contains two atoms of Br, so there are

<em>2 × Avogadro’s number of Br atoms </em>in 1 mol Br₂.

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3 years ago
If the initial velocity of the car in the previous problem (the car accelerates at 5.00 km/hr/s for 3.50 sec) is 22.6 km/hr, wha
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Answer:

1. B, D,

2.A, F

Explanation:

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