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____ [38]
2 years ago
6

All of the following are equal to Avogadro's number EXCEPT ____. a. the number of atoms of bromine in 1 mol Br2 b. the number of

atoms of gold in 1 mol Au c. the number of molecules of nitrogen in 1 mol N2 d. the number of molecules of carbon monoxide in 1 mol CO
Chemistry
1 answer:
Colt1911 [192]2 years ago
8 0

All the following are equal to Avogadro's number EXCEPT a. the number of atoms of bromine in 1 mol Br₂.

1 mol Br₂ contains Avogadro’s number of molecules of Br₂.

However, each molecule contains two atoms of Br, so there are

<em>2 × Avogadro’s number of Br atoms </em>in 1 mol Br₂.

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When sodium and oxygen react to form an ionic compound, the mass of the compound ____ the sum of the masses of the individual el
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250 ml glass of lemon juice contains 20 grams of sugar. How much sugar is in 500 ml bottle
iren2701 [21]

There is 40 g of sugar in a 500 ml bottle of lemon juice

<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

the concentration of sugar in lemon juice :

\tt \dfrac{20~g}{250~ml}=0.08~g/ml

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5 0
3 years ago
Find the percent composition of OXYGEN in Manganese (III) nitrate, Mn(NO3)3.
BaLLatris [955]

Answer:

59.8%

Explanation:

First find the Mr of manganese (III) nitrate.

Mr of Mn(NO₃)₃ = 54.9 + (14 × 3) + (16 × 3 × 3) = <u>240.9</u>

Since we have to find the percentage composition of oxygen, we need to find the Mr of oxygen in the compound, which is:

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Now we can find percentage composition / percentage by mass of oxygen.

% composition = \frac{Mr\ of\ oxygen\ in\ compound}{Mr\ of\ compound} × 100

% composition = \frac{144}{240.9} × 100 = <u>59.776%</u>

∴ % compostion of oxygen in maganese(III)nitrate is 59.8% (to 3 significant figures).

8 0
2 years ago
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