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Marysya12 [62]
3 years ago
11

The jet stream is one of the key winds that moves air masses. In which direction does the jet stream in the United

Chemistry
1 answer:
s344n2d4d5 [400]3 years ago
6 0

Answer: west to east

Explanation:

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If the reduction reaction has a reduction potential of 0.1 V, and the oxidation reaction has a reduction potential of -0.4V, and
aleksley [76]

Answer : The value of ΔG expressed in terms of F is, -1 F

Explanation :

First we have to calculate the standard electrode potential of the cell.

E^o=E^o_{cathode}-E^o_{anode}

or,

E^o=E^o_{reduction}-E^o_{oxidation}

E^o=(0.1V)-(-0.4V)=+0.5V

Now we have to calculate the standard cell potential.

Formula used :

\Delta G^o=-nFE^o

where,

\Delta G^o = Gibbs free energy = ?

n = number of electrons = 2

F = Faraday constant

E^o = standard e.m.f of cell = +0.5 V

Now put all the given values in this formula, we get the Gibbs free energy.

\Delta G^o=-(2\times F\times 0.5)

\Delta G^o=-1F

Therefore, the value of ΔG expressed in terms of F is, -1 F

5 0
3 years ago
What is the frequency of a light that has a wavelength of 3.0 x 10 -7m?
alexdok [17]

Answer:

 frequency of light (f) = 1 x 10¹⁵s⁻¹

Explanation:

Given Data:

Wavelength of light λ = 3.0 x10⁻⁷m

Frequency of light: to be calculated

Formula Used to find frequency:

                                  f = V/λ ........................... (1)

where

f is the frequency

V is the velocity

λ is wavelength

Velocity of light = 3 x 10⁸ ms⁻¹

put the values in equation (1)

                                     f =  3 x 10⁸ ms⁻¹ / 3.0 x10⁻⁷m

                                     f = 1 x 10¹⁵s⁻¹

   So the frequency of light =  1 x 10¹⁵s⁻¹

7 0
2 years ago
The temperature of 15.71 grams of gold rises from 32°C to 1,064°C, and then the gold melts completely. If gold’s specific heat i
antoniya [11.8K]

Answer:Total energy gained by 15.71 g is 3090.6471 joules

Explanation:

Given:

Q = heat gained by the 15.71 gram mass of gold

Q=mc\Delta T +m\Delta H_{fusion}

\Delta T=(T_{final}-T_{initial})=(1064^oC-32^oC)=1032^oC

c = specific heat capacity of gold = 0.1291joules/gram^oC

m = mass of gold =15.71 g

Q=15.71 g\times 0.1291 joules/gram^oC (1032^oC) +15.71 g\times 63.5 Joules/gram

Heat gained by gold = 2093.0621 Joules + 997.585 Joules

=3090.6471 joules

6 0
3 years ago
Worth 20 points will mark you brainliest!
alexgriva [62]
The one u clicked is the the right one
5 0
2 years ago
The transition metals are located in what block of the periodic table
gladu [14]
Located in the D block
7 0
3 years ago
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