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2 years ago

How many moles of NaCl are needed to produce 5 L of a 2. 4 M solution?

Chemistry

1 answer:

dsp732 years ago

6 0

Molarity=Moles of solute/Volume of solution in L

Put values

2.4M=moles of NaCL/5L
Moles of NaCL=2.4(5)
Moles of NaCl=12mol

Ans is 12mol

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The statements in the table summarize what Johannes Kepler stated in the early 1600s about the motion of planets.

SIZIF [17.4K]

Answer:

it's law

Explanation:

i got it wrong because i put the wrong answer but it was law or c

i hope this help's

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3 years ago

What type of nuclear decay is shown by the reaction below?

pantera1 [17]

Answer:

B. Alpha

Explanation:

Alpha decays always split into an element and He.

Beta decays always split into an element and e- (eletrons).

Gamma decays always split into an element and radiation.

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3 years ago

(4) Calculate the % of a compound that can be removed from liquid phase 1 by using ONE to FOUR extractions with a liquid phase 2

maksim [4K]

Answer:

One extraction: 50%

Two extractions: 75%

Three extractions: 87.5%

Four extractions: 93.75%

Explanation:

The following equation relates the fraction q of the compound left in volume V₁ of phase 1 that is extracted n times with volume V₂.

qⁿ = (V₁/(V₁ + KV₂))ⁿ

We also know that V₂ = 1/2(V₁) and K = 2, so these expressions can be substituted into the above equation:

qⁿ = (V₁/(V₁ + 2(1/2V₁))ⁿ = (V₁/(V₁ + V₁))ⁿ = (V₁/(2V₁))ⁿ = (1/2)ⁿ

When n = 1, q = 1/2, so the fraction removed from phase 1 is also 1/2, or 50%.

When n = 2, q = (1/2)² = 1/4, so the fraction removed from phase 1 is (1 - 1/4) = 3/4 or 75%.

When n = 3, q = (1/2)³ = 1/8, so the fraction removed from phase 1 is (1 - 1/8) = 7/8 or 87.5%.

When n = 4, q = (1/2)⁴ = 1/16, so the fraction removed from phase 1 is (1 - 1/16) = 15/16 or 93.75%.

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3 years ago

according to the balanced chemical equation below,how many grams of h20 are produced if 3.98g of co2 were produced. 2C18H18 + 25

telo118 [61]

Answer:

Primero debes usar los gramos de co2 y luego buscar su peso molecular, luego de eso usar la relación de moles entre CO2 y H2O y por último buscar el pm del H2O pata ver cuantos gramos de produce.

Explanation:

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3 years ago

Identify each statement as true or false. Explain in every case.a.Ionization energies are always negative quantities.b.Oxygen ha

worty [1.4K]

Answer:

(a) FALSE

(b) FALSE

(d) FALSE

Explanation:

Ionization energy refers to the energy needed for removal of a valence electron present in valence shell of a gaseous atom.

(a) The value of ionization energy of an atom is always positive. This is because energy has to be always supplied or provided to a gaseous atom for the removal of the valence electron.

Therefore, the statement (A) is false

(b) The ionization energy of an atom increases across a period i.e. from left to right. This is because the effective nuclear charge that is experienced by the valence electron increases from left to right in the periodic table, as the atomic number increases.

So, more energy is required to remove the valence electron of fluorine as compared to oxygen.

Therefore, the ionization energy of fluorine is greater than oxygen.

Therefore, the statement (B) is false

(c) First ionization energy is energy needed for removal of first electron present in valence shell of a neutral atom. Whereas, second ionization energy is the energy needed for removal of second electron present in valence shell of a monovalent cation

The second ionization energy of an atom is always greater than the first ionization energy. This is because removing an electron from a positively charged species, requires more energy.

Therefore, the statement (C) is true

(d) The third ionization energy refers to the energy needed to remove the third electron from a divalent cation.

Therefore, the statement (D) is false

7 0

3 years ago