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vampirchik [111]
2 years ago
6

If we accelerate a radioactive isotope of an element in a particle accelerator to a speed close to that of light, what would its

observed mass be compared to its mass at rest
Chemistry
1 answer:
Radda [10]2 years ago
8 0

When the speed of the particle is close to that of light, it's observed mass would be infinitely large.

To answer the question, we need to know what observed mass is.

<h3>What is observed mass in relativity?</h3>

This is the mass the body of an object in relativistic motion appears to have.

So, observed mass, m' = m/√(1 - β²) where

  • m = rest mass and
  • β = relative velocity of isotope to light.

Now, since the speed of the particle is close to that of light, β ≅ 1.

So, m' = m/√(1 - β²)

m' = m/√(1 - 1²)

m' = m/√(1 - 1)

m' = m/√0

m' = m/0

m' = ∞

So, when the speed of the particle is close to that of light, it's observed mass would be infinitely large.

Learn more about observed mass here:

brainly.com/question/14553472

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This question can be solved using Hess's Law.

Start by considering: how can the first three reactions (with known \Delta H values) be combined to produce the reaction \rm CH_4\; (g) + 4\; \rm Cl_2\; (g) \to CCl_4\; (g) + 4\; HCl\; (g)?

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In other words, if (1), (2), and (3) denote the three reactions with know \Delta H values, respectively, then 1 \times (1) - 1 \times (2) + 2\times (3) will give the required reaction \rm CH_4\; (g) + 4\; \rm Cl_2\; (g) \to CCl_4\; (g) + 4\; HCl\; (g).

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