The molecular formula of the compound is C12H15O3 hence the molar mass of the compound is 207 g/mol.
We need to obtain the number of moles of carbon, hydrogen and oxygen in the compound;
Carbon = 24.91 g/44g/mol × 1 mole of carbon = 0.566 moles
Mass of carbon = 0.566 moles × 12 g/mol = 6.792 g
Number of moles of hydrogen = 6.522 g/18 g/mol × 2 moles = 0.725 moles
Mass of hydrogen = 0.725 moles × 1 g/mol = 0.725 g
Mass of oxygen = 10 - (6.792 g + 0.725 g) = 2.483 g
Number of moles of oxygen = 2.483 g/16 g/mol = 0.155 moles
Now we must divide through by the lowest number of moles;
C - 0.566/0.155 H - 0.725/0.155 O - 0.155/0.155
C - 4 H - 5 O - 1
The simplest formula is C4H5O Recall that the molar mass of the compound lies between 150.0 and 220.0 g/mol
4(12) + 5(1) + 16 = 69
Hence; n = 3 and the molecular formula of the compound is C12H15O3
The molar mass of the compound is; 12(12) + 15(1) + 3(16) = 207 g/mol
Learn more: brainly.com/question/15180604
Answer:0.45L
Explanation:
molarity=0.15M
Mass=5g
No of moles=mass ➗ molecular mass
Molecular mass of KCL=39.0983x1+35.453x1
Molecular mass of KCL=74.5513
No of moles=5 ➗ 74.5513
No of moles=0.067
Volume in liters=No of moles ➗ molarity
Volume in liters=0.067 ➗ 0.15
Volume in liters=0.45L
Fuel......................................
Oxidation number of fe in the compound...,
Let the oxidation number of (Fe) be x
The oxidation number of oxygen(o) is (-2)
; 3x + 4(-2) = 0...where zero is the total charge on the compound(fe3o4)
; 3x = 8...then divide both sides by 3
Oxidation number of fe is( 2.67 )
