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Otrada [13]
3 years ago
10

If I have 20g of Sodium, how many moles of Sodium Oxide (Na2O) can be made?

Chemistry
1 answer:
Vika [28.1K]3 years ago
8 0
Mass:20g

Mole=20/[2(23)+16]
=0.32 mil
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Metals only and ionic
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Mineral oil dissolves in hexane but not in ethanol
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That would be correct as stated.
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If you have a 150-gram sample of CrO3: • How many moles of CrO3 do you have? • How many oxygen atoms do you have? • How many gra
docker41 [41]

Answer :

(a) The moles of CrO_3 is, 1.5 moles.

(b) The number of oxygen atoms are, 27.099\times 10^{23}

(c) The mass of oxygen is, 72 grams.

Explanation : Given,

Mass of CrO_3 = 150 g

Molar mass of CrO_3 = 100 g/mole

Molar mass of oxygen = 16 g/mole

(a) First we have to calculate the moles of CrO_3.

\text{Moles of }CrO_3=\frac{\text{Mass of }CrO_3}{\text{Molar mass of }CrO_3}=\frac{150g}{100g/mole}=1.5moles

The moles of CrO_3 is, 1.5 moles.

(b) Now we have to calculate the number of oxygen atoms.

In CrO_3, there are 1 atom of chromium and 3 atoms of oxygen.

According to the mole concept,

1 mole of CrO_3 contains 3\times 6.022\times 10^{23} number of oxygen atoms.

So, 1.5 mole of CrO_3 contains 1.5\times 3\times 6.022\times 10^{23}=27.099\times 10^{23} number of oxygen atoms.

The number of oxygen atoms are, 27.099\times 10^{23}

(c) Now we have to calculate the mass of oxygen.

As, 1 mole of CrO_3 contains 3 moles of oxygen

So, 1.5 mole of CrO_3 contains 1.5\times 3=4.5 moles of oxygen

\text{Mass of oxygen}=\text{Moles of oxygen}\times \text{Molar mass of oxygen}

\text{Mass of oxygen}=(4.5mole)\times (16g/mole)=72g

The mass of oxygen is, 72 grams.

3 0
3 years ago
The solubility of N2 in blood at 37°C and a partial pressure of 0.80 atm is 5.6 ✕ 10−4 mol·L−1. A deep-sea diver breathes compre
marysya [2.9K]

Answer:

0.0126 moles are released

Explanation:

Using Henry's law, where the amount of dissolved gas in a liquid is proportional to its partial pressure above the liquid:

S = k×P

<em>Where S is solubility (5.6x10⁻⁴molL⁻¹), k is Henry's constant and P is partial pressure (0.80atm)</em>

Replacing:

<em>5.6x10⁻⁴molL⁻¹ / 0.80atm = 7x10⁻⁴molL⁻¹atm⁻¹</em>

Thus, with Henry's constant, solubility of N₂ when partial pressure is 3.8atm is:

S = 7x10⁻⁴molL⁻¹atm⁻¹ × 3.8atm

S = 2.66x10⁻³molL⁻¹

Thus, when the deepd-sea diver has a pressure of 3.8amt, moles dissolved are:

6.0L × 2.66x10⁻³molL⁻¹ = <em>0.01596 moles of N₂</em>

At the surface, pressure is 0.80atm and solubility is 5.6x10⁻⁴molL⁻¹, moles dissolved are:

6.0L × 5.6x10⁻⁴molL⁻¹ = <em>3.36x10⁻³mol</em>

Thus, released moles are:

0.01596mol - 3.36x10⁻³mol = <em>0.0126 moles are released</em>

8 0
3 years ago
A force has to have which two Factors
monitta
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4 0
3 years ago
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