Answer:
295.7 mL of 24% trichloroacetic acid (tca) is needed .
Explanation:
Let the volume of 24% trichloroacetic acid solution be x
Volume of required 10% trichloroacetic acid solution =8 bottles of 3 ounces
= 24 ounces = 709.68 mL
(1 ounces = 29.57 mL)
Amount of trichloroacetic acid in 24% solution of x volume of solution will be equal to amount of trichloroacetic acid in 10% solution of volume 709.68 mL.

x = 295.7 mL
295.7 mL of 24% trichloroacetic acid (tca) is needed .
I believe the answer is C, n = 3, l = 3, m = 3. The magnetic quantum number, or
<span>ml</span>, can only take values that range from <span>−l</span> to <span>+l</span>, as you can see in the table above.
For option C), the angular momentum quantum number of equal to ++2<span>, which means that <span>ml</span> can have a maximum value of </span>+2<span>. Since it is given as having a value of </span>+3**, this set of quantum numbers is not a valid one.
The other three sets are valid and can correctly describe an electron.
Since they can still be unstable...nuetral atoms have the same amount of protons to electrons but to be stable they need to fill up there outer shell by gaining or losing electrons
C. PH3 represents a compound commonly known as phosphine, whose IUPAC name is phosphorus trihydride.
<h3>What type of bond is PH3?</h3>
The electronegativity of PH3 found in the Periodic Table of the Period attracts covalent electron pairs and creates covalent bonds. However, because the electrons are not bound, asymmetrical rate distribution occurs. Therefore, PH3 is a polar molecule with a non-polar covalent bond and currently has no polar bond.
<h3 /><h3>What defines a covalent bond?</h3>
A covalent bond consists of sharing one or more electron pairs between two atoms. These electrons are attracted to two nuclei at the same time. Covalent bonds are formed when the difference in electronegativity between two atoms is too small for electron transfer to form ions.
Click here for more information on covalent bonds brainly.com/question/12732708
# SPJ10