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Lady_Fox [76]
2 years ago
11

What will be the substitution product of (S)-2-chloro-3-methylbutane in polar aprotic conditions favoring SN2?

Chemistry
1 answer:
Deffense [45]2 years ago
3 0
Almost there use socratic app



it will help


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How would an increase in the population affect the aquifer
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Groundwater pumping can alter how water moves between an aquifer. Hope this helps
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2 years ago
Balance the following SYNTHESIS chemical reaction with the correct coefficients:
kolbaska11 [484]

Answer:

b 2,3,1

Explanation:

2 Al + 3 S ----> Al2S3

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3 years ago
Complete this sentence: The total mass of the products in any chemical reaction is equal to
Komok [63]

Answer:

This law states that, despite chemical reactions or physical transformations, mass is conserved — that is, it cannot be created or destroyed — within an isolated system. In other words, in a chemical reaction, the mass of the products will always be equal to the mass of the reactants.

Explanation:

5 0
3 years ago
Read 2 more answers
t physiological pH, the carboxylic acid group of an amino acid will be ________, while the amino group will be ________, yieldin
astraxan [27]

Answer:

At physiological pH,the carboxylic acid group of an amino acid will be deprotonated while the amino group will be protonated,yielding the zwitter ion form.

Explanation:

Deprotonated means removal of protons in an acid base reaction and protonated means addition of protons in an acid base reaction.

Both protonated and de protonated reaction takes place in catalytic acid bade reaction by changing either it's mass or it's charge.

During formation of zwitter ion, the carboxylic acid will be deprotonated by donating the H+ ion while the amino acid is protonated by taking the H+ ion.

R-CH-COOH                               R-CH-COO-

   I                                ⇒                 I

  NH₂                                              NH₃               (Zwitter ion)

5 0
2 years ago
A 1.897g sample of Mg(HCO3)2 was heated and decomposed. When the sample
svlad2 [7]

1.5 % is the percent yield in the reaction.

Explanation:

Given that:

original mass of the sample used in reaction = 1.897 grams

product formed after decomposition = 1.071 grams

The reaction for the decomposition:

Mg(HCO3)2 (s) ⇒ CO2 (g) + H2O (g) + MgCO2 (s)

It says that 1 mole of Mg(HCO3)2  yielded 1 mole of  MgCO2  on decomposition

68.31 grams/mole or 68.31 grams of MgCO2 is formed

percent yield = \frac{actual yield}{theoretical yield} x 100

putting the values in the equation:

percent yield = \frac{1.071}{68.31}

                       = 0.015 x100

   PERCENT YIELD = 1.5 %

8 0
3 years ago
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