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UkoKoshka [18]
3 years ago
10

Which term is described as a flat expanse of ocean floor

Chemistry
2 answers:
liraira [26]3 years ago
8 0

the answer is guyots

makkiz [27]3 years ago
4 0
An abyssal plain......................................
You might be interested in
Eading and
4vir4ik [10]

Answer: 25.8 g of Cl_2 will be produced from the decomposition of 73.4 g of AuCl_3

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} AuCl_3=\frac{73.4g}{303g/mol}=0.242moles

The balanced chemical reaction is:

2AuCl_3\rightarrow 2Au+3Cl_2  

According to stoichiometry :

2 moles of AuCl_3 produce =  3 moles of Cl_2

Thus 0.242 moles of  will produce= \frac{3}{2}\times 0.242=0.363mol of Cl_2

Mass of Cl_2= moles\times {\text {Molar mass}}=0.363mol\times 71g/mol=25.8g

Thus 25.8 g of Cl_2 will be produced from the decomposition of 73.4 g of AuCl_3

5 0
2 years ago
Which of the following demonstrates a double-replacement reaction?
Volgvan
A: Na3PO4 + MnCl2 > Mn3(PO4)2 + NaCl
6 0
3 years ago
Read 2 more answers
_____ Na3PO4 + _____ KOH   arrow  _____ NaOH + ___________K3PO4 <br> How do I balance this equation?
soldi70 [24.7K]
The answer is na3po4+3koh=3naoh+k3po4
6 0
3 years ago
The masses of carbon and hydrogen in samples of four pure hydrocarbons are given above. The hydrocarbon in which sample has the
enot [183]

Answer:

Sample B

Explanation:

In this case, we need to determine the empirical formula for each sample. The one that match the formula of the propene would be the sample.

Let's do Sample A:

C: 60 g;       H: 12 g

1. Calculate moles:

We need the atomic weights of carbon (12 g/mol) and hydrogen (1 g/mol):

C: 60 / 12 = 5

H: 12 / 1 = 12

2. Determine number of atoms in the formula

In this case, we just divide the lowest moles obtained in the previous part, by all the moles:

C: 5 / 5 = 1

H: 12 / 5 = 2.4    or rounded to two

3. Write the empirical formula:

Now, the prior results, represent the number of atoms in the empirical formula for each element, so, we put them with the symbol and the atoms as subscripted:

C₁H₂ = CH₂

Therefore, sample A is not the same as propene.

Sample B:

C: 72 g    H: 12 g

Following the same steps, let's determine the empirical formula for this sample

C: 72 / 12 = 6 ---> 6 / 6 = 1

H: 12 / 1 = 12 ----> 12 / 6 = 2

EF: CH₂

Sample C:

C: 84 g    H: 10 g

C: 84 / 12 = 7 ----> 7 / 7 = 1

H: 10 / 1 = 10    ----> 10 / 7 = 1.4 or just 1

EF: CH

Sample D

C: 90 g      H: 10 g

C: 90 / 12 = 7.5     -----> 7.5 / 7.5 = 1

H: 10 / 1 = 10  -------> 10 / 7.5 = 1.33 or just 1

EF: CH

Neither compound has the same empirical formula as C3H6, but C3H6 is a molecular formula, so, if we just simplify the formula we have:

C3H6  -----> CH₂

Therefore, sample B is the one that match completely. Sample B would be the one.

Hope this helps

8 0
3 years ago
What is the molarity of 5.74 liters of solution made with 246 grams of iron (III) chloride (FeCl3)? Answer with 3 SDs.
geniusboy [140]

Answer:

0.264 mol/L

Explanation:

Data obtained from the question includes:

Volume = 5.74L

Mass of FeCl3 = 246 g

Molarity =?

Next, we shall determine the number of mole in 246g of FeCl3.

This is illustrated below:

Mass of FeCl3 = 246g

Molar mass of FeCl3 = 56 + (35.5x3) = 162.5g/mol

Number of mole of FeCl3 =..?

Mole = Mass /Molar Mass

Number of mole of FeCl3 = 246/162.5

Number of mole of FeCl3 = 1.514 mol

Now, we can obtain the molarity of the solution as follow:

Molarity = mole /Volume

Volume = 5.74L

Mole of FeCl3 = 1.514 mol

Molarity = 1.514/5.74

Molarity = 0.264 mol/L

5 0
3 years ago
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