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3 years ago

Find the perimeter of the triangle shown using the Associative proprety. 4 1/2 in 5 1/2in 6 in

1 answer:

3 0

So assumn that the measures given are the legnths of the sides
perimiter=side1+side2+side3
so
side1=4 and 1/2
side2=5 and 1/2
side3=6
subsitute
p=(4+1/2)+(5+1/2)+(6)
associative prpoerty says (a+b)+c=a+(b+c) (it deals with addiont with parenthasees)
p=4+1/2+5+1/2+6
p=4+5+1/2+1/2+6
p=9+1+6
p=10+6
p=16 inches

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What is the area, in square inches, of the rectangle below?

chubhunter [2.5K]

The answer would be D i believe

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2 years ago

The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

5 0

3 years ago

How to do RX - sx + y equals B plzz explain how to get the answer there all variables!!!!

zalisa [80]

Rx - sx + y = b

WHEN SOLVING FOR X :

rx - sx + y = b

We must get x onto it's own side, so subtract y from both side.s

rx - sx = b - y

Then, factor out x.

x(r - s) = b - y

Then, divide both sides by (r - s).

x(r - s) ÷ (r - s) = b - y ÷ (r - s)

Simplify.

x = b - y / r - s → $x = \frac{b-y}{r-s}$

WHEN SOLVING FOR Y :

rx - sx + y = b

We need to isolate y, so get rid of everything BUT y on the left side.

Subtract rx from both sides.

-sx + y = b - rx

Then, add sx to both sides.

y = b - rx + sx

~Hope I helped!~

5 0

3 years ago

For a school play, the teacher asked the class to set up chairs in 20 rows with 25 chairs in each row. After setting up all the

pantera1 [17]

20 rows * 25 chairs=500 chairs
500-5=495
Answer=495

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3 years ago

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Two students are standing 20ft apart and spot Mrs. Rose. If they immediately run opposite directions with speeds of 300ft/min an

bonufazy [111]

They would be separating at 500 ft/min

time to go 3000 ft at that speed

= 3000/500 min

= 6 minutes

this may help you

4 0

3 years ago