How to factor 3n^2+3n-60

Mathematics

2 answers:

sveta [45]3 years ago

6 0

$3n^2+3n-60 =\\
3(n^2+n-20)=\\
3(n^2+5n-4n-20)=\\
3(n(n+5)-4(n+5))=\\
3(n-4)(n+5)$

Digiron [165]3 years ago

4 0

Factour out the 3 first
3(n^2+n-20)
what 2 numbers muliplty to get -20 and add to get 1
-4 and 5
3(n-4)(n+5)

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