Answer:
a. t
b. a (or x = a)
c. r
d.
1) c
2) t
3) a
4) p
Step-by-step explanation:
a. Draw vertical line passing through the point (c,0). This line intersects the graph at point L. Point L has coordinates (c,t), so
b. If 
draw the horizontal line passing through the point (0,p). This line intersects the graph at point K with coordinates (a,p), so 
c. Note that 
then
d. Coordinates of point L are (c,t), coordinates of point K are (a,p)
This is a very interesting problem. What makes it so interesting is that
there's so little actual math to it. The only big Math thing you need to know
in order to work with this question is the definition of "perimeter".
"Perimeter" means
"the distance all the way around the edge of something".
The problem GIVES you the length of all the sides of both triangles.
To find the perimeter of one triangle, just take the lengths of its three
sides and addum up.
The perimeter of the blue one is (7x+7) + (5x-4) + (4x+2) .
That's it ! That's the perimeter. Of course, they want you to write
it in simplest form, so you have to clean it up. Remove all of the
parentheses, add up all the 'x's, and add up all the plain numbers,
and you'll have a short, pretty expression.
Then do the same thing for the red one, and get its perimeter.
In part-b, they want you to find the difference between the two perimeters.
No problem. Just write (the blue perimeter) minus (the red perimeter),
and simplify THAT expression.
Now they want the actual perimeters when 'x' is 3.
No big deal. Just take each separate perimeter, write '3' in place of 'x',
and find the number that the expression becomes.
Just now, looking at the picture without writing anything down,
I got 53 for the blue one and 17 for the red one.
I could easily be wrong, so you definitely have to work them
out for yourself.
Answer:
416 I believe.
Step-by-step explanation:
add 7 to 149
divide 156 by 3 to get 1/8 of total.
Get 52 and then multiply by 8 to get 416
Answer:
the dividend is 2x^3 + 10x^2 + x + 5
Step-by-step explanation:
I took the test and I got a 100%
