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Vaselesa [24]
3 years ago
15

Which reactants would lead to a spontaneous reaction?

Chemistry
1 answer:
Igoryamba3 years ago
3 0

Answer:

B. Ba2+ and Mn (nevermind its not B)

Explanation:

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1. Sodium hydroxide reacts with carbon dioxide according to the equation: 2NaOH(s) + CO2(g) →
Leno4ka [110]

The limiting reagent when 5 g of NaOH and 4.4 g CO₂  allowed to react will be NaOH

<h3>What is Limiting reagent ?</h3>

The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.

Given chemical equation in balanced form ;

2NaOH(s) + CO₂(g) → Na₂CO₃(s) + H₂O(l).

According to the Chemical equation ;

  • The limiting reagent when 5 g of NaOH and 4.4 g CO₂  allowed to react will be NaOH

    If 44 g CO₂ requires 80 g of NaOH, therefore, 4.4 g CO₂ will require atleast 8 g of NaOH.

    But the available quantity is 5 g NaOH. thus, NaOH is the Limiting reagent.

  • 6.625 g of Na₂CO₃ are expected to be produced 5.0 g of NaOH and 4.4 g of CO₂ are allowed to react

    As 80 g NaOH produces 106 g of Na₂CO₃.

    Therefore 5 g NaoH will produce ;

    106 / 80 x 5 = 6.625 g

Learn more about limiting reagent here ;

brainly.com/question/11848702

#SPJ1

5 0
2 years ago
Is it necessary to prepare sodium extract to detect nitrogen in urea ?​
Vilka [71]

Answer:

I think No

Explanation:

7 0
2 years ago
How many significant figures are in 1.009 L
NeTakaya
4


Numbers above zero are significant, as well as any zeros that appear in between two non-zero numbers.
8 0
2 years ago
If the rate of a reaction increases by a factor of 64 when the concentration of reactant increases by a factor of 4, what is the
igomit [66]

The reaction is of order three with respect to the reactant.

<h3>Explanation</h3>

The rate of a reaction of order n about a certain reactant is proportion to the concentration of that reactant raised to the n-th power. This is true only if  concentrations of any other reactants stay constant in the whole process.

In other words, Rate = constant × [Reactant]ⁿ, Rate ∝ [Reactant]ⁿ. (The symbol "∝" reads "proportional to".)

In this question,

[4 × Reactant]ⁿ ÷ [Reactant]ⁿ = 64.

In other words, 4ⁿ = 64, where n is the order of the reaction with respect to this reactant.

It might take some guesswork to find the value of n. Alternatively, n can be solved directly with a calculator using logarithms. Taking natural log of both sides:

\ln{4^n} = \ln{64}\\n\; \ln{4} = \ln{64}\\n = \frac{\ln{64}}{\ln{4}} = 3.

Evaluating \ln(64) / \ln(4) on Google or on a calculator with support for ln (the natural log) will give the value of n- no guesswork required.

n = 3. Therefore, the reaction is of order three with respect to this reactant.

3 0
3 years ago
You have equal masses of different solutes dissolved in equal volumes of solution. Which of the solutes would make the solution
Aleonysh [2.5K]

Answer:

The highest molar concentration is in the solution of potassium chloride because it's the one, with the highest molar mass.

Explanation:

If we have the same mass and the same volume in all the solutes and solutions, we should know the molar mass for each, to calculate how many moles of solute are we having.

a. LiOH → 23.94 g/m

b. KCl → 74.55 g/m

c. KOH → 56.1 g/m

d. NaOH → 40 g/m

The highest molar mass is in option b. It will have the most moles.

3 0
3 years ago
Read 2 more answers
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