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Vaselesa [24]
3 years ago
15

Which reactants would lead to a spontaneous reaction?

Chemistry
1 answer:
Igoryamba3 years ago
3 0

Answer:

B. Ba2+ and Mn (nevermind its not B)

Explanation:

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Lostsunrise [7]

Answer:

Punnett Square

Explanation:

7 0
3 years ago
Read 2 more answers
A person uses a pulley to raise a flag up a 15 meter flagpole. The weight of
GREYUIT [131]

Answer:

Explanation:

I burnt my ramen noodles today :) <3 help me <3 I need somewhere to live

8 0
3 years ago
What is the standard electrode potential for a galvanic cell constructed in the appropriate way from these two half-cells?
____ [38]

E

θ

Cell

=

+

2.115

l

V

Cathode

Mg

2

+

/

Mg

Anode

Ni

2

+

/

Ni

Explanation:

Look up the reduction potential for each cell in question on a table of standard electrode potential like this one from Chemistry LibreTexts. [1]

Mg

2

+

(

a

q

)

+

2

l

e

−

→

Mg

(

s

)

−

E

θ

=

−

2.372

l

V

Ni

2

+

(

a

q

)

+

2

l

e

−

→

Ni

(

s

)

−

E

θ

=

−

0.257

l

V

The standard reduction potential

E

θ

resembles the electrode's strength as an oxidizing agent and equivalently its tendency to get reduced. The reduction potential of a Platinum-Hydrogen Electrode under standard conditions (

298

l

K

,

1.00

l

kPa

) is defined as

0

l

V

for reference. [2]

A cell with a high reduction potential indicates a strong oxidizing agent- vice versa for a cell with low reduction potentials.

Two half cells connected with an external circuit and a salt bridge make a galvanic cell; the half-cell with the higher

E

θ

and thus higher likelihood to be reduced will experience reduction and act as the cathode, whereas the half-cell with a lower

E

θ

will experience oxidation and act the anode.

E

θ

(

Ni

2

+

/

Ni

)

>

E

θ

(

Mg

2

+

/

Mg

)

Therefore in this galvanic cell, the

Ni

2

+

/

Ni

half-cell will experience reduction and act as the cathode and the

Mg

2

+

/

Mg

the anode.

The standard cell potential of a galvanic cell equals the standard reduction potential of the cathode minus that of the anode. That is:

E

θ

cell

=

E

θ

(

Cathode

)

−

E

θ

(

Anode

)

E

θ

cell

=

−

0.257

−

(

−

2.372

)

E

θ

cell

=

+

2.115

Indicating that connecting the two cells will generate a potential difference of

+

2.115

l

V

across the two cells.

5 0
2 years ago
Read 2 more answers
Building Vocabulary
Juliette [100K]

Answer:

Explanation:

Building Vocabulary

Match each term with its definition by writing the letter of the correct definition on

the line beside the term in the left column.

5. nucleus   b

6. proton     f

7. neutron   h

8. electron  d

9. atomic number    g

10. isotopes              c

11. mass number      a

12. energy level       e

a. the sum of protons and neutrons in the nucleus of an

atom

b. the very small center core of an atom

c. atoms of the same element that differ in the number

of neutrons, but have the same number of protons

d. the particle of an atom that moves rapidly in the

space outside the nucleus

e. a specific amount of energy related to the movement

of electrons in atoms

f. the particle of an atom with a positive charge

g. the number of protons in the nucleus of every atom

of an element

h. the particle of an atom that is neutral

-. mass number  a.

12. energy level    e

5 0
2 years ago
Calculate the pH and pOH of 500.0 mL of a phosphate solution that is 0.285 M HPO42– and 0.285 M PO43–. (Ka for HPO42- = 4.2x10-1
jekas [21]

Answer: when concentrations of acid and base are same, pH = pKa

PH = 12.38 pOH = 1.62

Explanation: pKa= -log(Ka)= 12.38. PH + pOH = 14.00

8 0
3 years ago
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