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baherus [9]
3 years ago
9

How many moles of co are contained in a 5.00 l tank at 155°c and 2.80 atm?

Chemistry
1 answer:
seropon [69]3 years ago
4 0

Answer:

There are 0.408 moles of CO

Explanation:

Ideal gases Law to solve this excersise

P . V = n . R . T

Pressure = 2.80 atm

Volume = 5 L

T° = 155°C

T° K = T°C + 273 = 428K

R = 0.082 l.atm/mol.K

2.80 atm . 5l = n . 0.082 . 428K

(2.80 atm . 5l) / (0.082 . 428K) = n

0.408 mol = n

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Explanation:

Hello!

In this case, since the combustion reaction of methanol is:

CH_3OH+\frac{3}{2} O_2\rightarrow CO_2+2H_2O

In such a way, since there is 1:3/2 mole ratio between methanol and oxygen, we can compute the moles of oxygen that are needed to burn 2.56 moles of methanol as shown below:

n_{O_2}=2.56molCH_3OH*\frac{\frac{3}{2}molO_2}{1molCH_3OH} \\\\n_{O_2}=3.84molO_2

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