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Karo-lina-s [1.5K]
3 years ago
7

Choose the element that IS NOT in the same period as Potassium.

Chemistry
1 answer:
Lesechka [4]3 years ago
8 0
E. sodium is the answer

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Nitrogen dioxide is a red-brown gas that is responsible for the color of photochemical smog. What is the volume of 1 mol of nitr
Ray Of Light [21]
B ideal gas has a volume of 22.4
5 0
3 years ago
A 1.87 L aqueous solution of KOH contains 155 g of KOH . The solution has a density of 1.29 g/mL . Calculate the molarity ( M ),
Semenov [28]

Answer:        

[KOH] : 1.47 M

[KOH] : 1.22 m

[KOH]: 6.42 % mass percent.      

Explanation:

First of all we must determine the volume of solution. We have to work with the density

Density = mass / volume

1.29 g/ml = mass / 1870 ml

1.29 g/ml . 1870 ml = 2412.3

Now we must convert the mass to moles

155g / 56.1 g/ mol = 2.76 moles

Now we can calculate molarity

2.76 mol / 1.87 L = 1.47 M

To calculate molality we have to find out the mass of solvent

mass solute + mass solvent = mass solution

155 g + mass solvent = 2412.3 g

2412.3g - 155g = 2257.3g

We have to convert the 2257.3 g to kg

2257.3 g = 2.25 kg

molality = 2.76 moles / 2.25 kg = 1.22 m

To find out the % mass percentation, we have to calculate the mass of solute in 100 g of solution.

In 2412.3 g of solution we have 155 g of KOH

In 100 g of solution, we would have (100 . 155) / 2412.3 = 6.42 %mass percent.

7 0
3 years ago
The shape of a molecule is trigonal planar. How many electron domains around the central atom does this molecule most likely hav
soldi70 [24.7K]
I would think that the answer would be three

Because of the prefix tri- in "tigonal"

Tri- means 3, as in tricycle or triangle

So, it would make sense for the answer to be 3
8 0
3 years ago
Read 2 more answers
Why are alkalis sometimes<br> described as the opposite of<br> acids?
zlopas [31]

Answer: Because Alkalis are bases that can dissolve in water, which can also neutralize acid.

7 0
3 years ago
Determine the concentration of H+ in each solution at 25∘C
puteri [66]

Answer:

1: [H+] = 0.01 M

2: [H+] = 0.0001 M

3: [H+] = 0.0001 M

Explanation:

Step 1: data given

pH = -log[H+]

pH = pOH = 14

Step 2:

1. A solution with pH = 2.0

pH = 2

-log[H+] = 2.0

[H+] = 10^-2

[H+] = 0.01 M

2. A solution with pH = 4.0

pH = 4

-log[H+] = 4.0

[H+] = 10^-4

[H+] = 0.0001 M

3. A solution with pOH = 10.0

pH = = 14 - 10 = 4

pH = 4

-log[H+] = 4.0

[H+] = 10^-4

[H+] = 0.0001 M

4 0
3 years ago
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