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Lisa [10]
4 years ago
10

draw the structure of the isomer that have the molecular formula C5H11Br that is incapable of reacting by E2 mechanism

Chemistry
1 answer:
kozerog [31]4 years ago
8 0
Elimination cannot take place if the adjacent Carbon atom has no immediately bonded Hydrogen atom. An isomer of this will by:
(CH₃)₃C-CH₂Br
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the empirical formula of a compound is NO2. it's molecular mass is 92g/mol. What is its molecular formula?
lesantik [10]
The molecular formula:
N_x(O_2)_x

M_{N_x(O_2)_x}=x \times M_N + x \times 2 \times M_O \\ \\
m_N=14 \ \frac{g}{mol} \\
m_O=16 \ \frac{g}{mol} \\ M_{N_x(O_2)_x}=92 \ \frac{g}{mol} \\ \\
92=x \times 14+x \times 2 \times 16 \\
92=14x+32x \\
92=46x \\
\frac{92}{46}=x \\
x=2 \\ \\
N_2(O_2)_2 \Rightarrow N_2O_4

The molecular formula is N₂O₄.
8 0
3 years ago
Rows are known as what
Anestetic [448]
The rows are known as PERIODS and the columns are know as GROUPS.
8 0
3 years ago
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Please help i will mark you
Bad White [126]

Answer:

an oven cooking food

Explanation:

when it's off it has mechanical energy, when on it has electrical energy transformed to heat energy.

7 0
3 years ago
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Question 26 Suppose a flask is filled with of and of . The following reaction becomes possible: The equilibrium constant for thi
Blizzard [7]

Answer:

0.36 M

Explanation:

There is some info missing. I think this is the complete question.

<em>Suppose a 250 mL flask is filled with 0.30 mol of N₂ and 0.70 mol of NO. The following reaction becomes possible: </em>

<em>N₂(g) +O₂(g) ⇄ 2 NO(g) </em>

<em>The equilibrium constant K for this reaction is 7.70 at the temperature of the flask.  Calculate the equilibrium molarity of O₂. Round your answer to two decimal places.</em>

<em />

Initially, there is no O₂, so the reaction can only proceed to the left to attain equilibrium. The initial concentrations of the other substances are:

[N₂] = 0.30 mol / 0.250 L = 1.2 M

[NO] = 0.70 mol / 0.250 L = 2.8 M

We can find the concentrations at equilibrium using an ICE Chart. We recognize 3 stages (Initial, Change, and Equilibrium) and complete each row with the concentration or change in the concentration.

    N₂(g) +O₂(g) ⇄ 2 NO(g)

I    1.2        0              2.8

C  +x         +x            -2x

E  1.2+x      x           2.8 - 2x

The equilibrium constant (K) is:

K=7.70=\frac{[NO]^{2}}{[N_{2}][O_{2}]} =\frac{(2.8-2x)^{2} }{(1.2+x).x}

Solving for x, the positive one is x = 0.3601 M

[O₂] = 0.3601 M ≈ 0.36 M

7 0
3 years ago
Close friendships at work are often bad for the business. true or false and why?
LuckyWell [14K]

Explanation:

true true true true true true

6 0
3 years ago
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