It's lone a little distinction (103 degrees versus 104 degrees in water), and I trust the standard rationalization is that since F is more electronegative than H, the electrons in the O-F bond invest more energy far from the O (and near the F) than the electrons in the O-H bond. That moves the powerful focal point of the unpleasant constrain between the bonding sets far from the O, and thus far from each other. So the shock between the bonding sets is marginally less, while the repugnance between the solitary matches on the O is the same - the outcome is the edge between the bonds is somewhat less.
Answer:
the true statement is... The pH of the weak acid will be higher than the pH of the strong acid
Explanation:
pH is a measured of the extent to which acids dissociate into ions when plced in aqueous solution.
Strong acid dissociate near-completely, and weak acids barely dissociate.
At equal concentrations, a strong acid will have a lower pH than a weak acid, since the strong one will donate more proton to the solution.
The 2nd one I think but I need some points
It dissolves I think I know I am expert and. Ute
C is the answer.
It says on the third picture that Bohr refined Rutherford's model by giving distinct orbits for the electrons with distinct radii.
