Answer:
luster
i just did it and its luster
Answer:
(n, l, m, m(s)) => (Principle QN, Orbital QN, Magnetic QN, Spin QN)
Explanation:
n = row number => principle energy level n = 1 for Hydrogen (1st row), n = 2 for Lithium (2nd row), n = 3 for Sodium (3rd row) etc...
l = 0 => orbital QN => all have electrons entering s orbitals
m = 0 => orientation QN => spherical orbitals have m = 0
m(s) = +1/2 (1st e⁻) => spin QN
Answer:
1.4 g CaO
Explanation:
Given data:
Mass of calcium carbonate = 2.5 g
Mass of Cao remain in tube = ?
Solution:
Chemical equation:
CaCO₃ → CaO + CO₂
Number of moles of CaO:
Number of moles = mass/molar mass
Number of moles = 2.5 g/ 100 g/mol
Number of moles = 0.025 mol
now we will compare the moles of CaO with CaCO₃.
CaCO₃ : CaO
1 : 1
0.025 : 0.025
Mass of CaO:
Mass = number of moles × molar mass
Mass = 0.025 mol × 56 g/mol
Mass = 1.4 g
Answer:
V KOH = 247.939 mL
Explanation:
at the point of equilibrium:
mol CH3COOH = mol KOH.......for weak acid system - strong bases...(1)
⇒ mol CH3COOH = 0.775L * 0.819 mol / L
⇒ mol CH3COOH = 0.634 mol CH3COOH.....(2)
replacing (2) in (1):
0.634 mol = V KOH * 2.56 mol / L
⇒ V KOH = 0.634 mol / (2.56 mol / L )
⇒ V KOH = 0.247939 L ( 247.939 mL )
M(Mn(ClO3)3)=(54.938)+(35.45x3)+(15.999x9)
M(Mn(ClO3)3)=305.279 g/mol