Answer:
171.34 g/mol
Explanation:
Ba molar mass = 137.328 g/mol
O molar mass = 15.999 g/mol * 2 = 31.9980 g/mol
H molar mass = 1.008 g/mol * 2 = 2.0160 g/mol
137.328 + 31.9980 + 2.0160 = 171.3420 = 171.34 g/mol
Answer:
By putting a coefficient 4 on NaI and 2 on Na₂SO₄
4NaI + Pb(SO₄)₂ → Pbi4 + 2Na₂SO₄
Explanation:
- A chemical equation is balanced for it to obey the law of conservation of mass.
- According to the law of conservation of mass, the mass of the reactants should be equal to the mass of products.
- Balancing involves putting coefficients on reactants and products to get an equal number of atoms of each element on either side of the equation.
- In this case, putting a coefficient four on NaI and two on Na₂SO₄ will make the equation to be balanced.
- Therefore, the balanced chemical equation is;
4NaI + Pb(SO₄)₂ → Pbi4 + 2Na₂SO₄
Answer:
.234 M
Explanation:
Molarity, or concentration, of a substance is simply found by dividing the amount of that substance in moles by its volume. Here, we are given the mass (in grams) of Kool-Aid, so we need to convert that to moles. To do this, we simply need the chemical formula of Kool-Aid, which I have found to be C12H22O11. The molar mass of C12H22O11, using the periodic table, is 342.296 g. Next, take this molar mass and divide the given mass of Kool-Aid by it. You then get about .234 mol Kool-Aid.
Lastly, divide this by the volume of 1.0 L. You get .234 M as your final molarity.
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Answer: The volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is LiOH.
We are given:
Putting values in above equation, we get:
Thus the volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml
