To show that TRK= TUK by the SAS postulate, what additional information is necessary?
2 answers:
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Answer:
(-2, 2)
Step-by-step explanation:
<u>Given:</u>
- Point A is at (2, -8) and point C is at (-4, 7)
<u>Difference of coordinates:</u>
- Δx = 2 - (-4) = 6
- Δy = - 8 - 7 = - 15
<u>The ratio of AB to AC is 2:1. So:</u>
- AB = 2*AC/3 and BC = AC/3
<u>Then coordinates of point B should be 2/3 from the point A:</u>
- x = 2- 6*2/3 = 2 - 4 = -2
- y = - 8 - (-15)*2/3 = -8 + 10 = 2
So point B has coordinates of (-2, 2)
Answer:
A
Step-by-step explanation:
Refer to the picture.
Step 1: expand the bracket
Step 2: bring like terms together (e. G. Numbers, algebra like terms)
Step 3: simplify equation
Step 4: rearrange algebraic form to see which order fits the answer.
Answer:
YES
NO
NO
Step-by-step explanation:
The given polynomial is:
(x - a) is a factor of a polynomial iff x = a is a solution to the polynomial.
To check if (x - 5) is a factor of the polynomial f(x), we substitute x = 5 and check if it satisfies the equation.
∴ f(5) = 5³ + 4(5)² - 25(5) - 100
= 125 + 100 - 125 - 100
= 225 - 225
= 0
We see, x = 5 satisfies f(x). So, (x - 5) is a factor to the polynomial.
Now, to check (x + 2) is a factor.
i.e., to check x = - 2 satisfies f(x) or not.
f(-2) = (-2)³ + 4(-2)² - 25(-2) - 100
= -8 + 16 + 50 - 100
= -108 + 66
≠ 0
Therefore, (x + 2) is not a factor of f(x).
To check (x - 4) is a factor.
∴ f(4) = 4³ + 4(4)² - 25(4) - 100
= 64 + 64 - 100 - 100
= 128 - 200
≠ 0
Therefore, (x - 4) is not a factor of f(x).