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3 years ago

To show that TRK= TUK by the SAS postulate, what additional information is necessary?

Mathematics

2 answers:

Anni [7]3 years ago

6 0

Answer:

RTK = UTK

Step-by-step explanation:

Korvikt [17]3 years ago

4 0

Answer:

RTK =UTK

Step-by-step explanation:

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Bject?

Yakvenalex [24]

Answer:

The entire volume would be 60m, but if it's talking only about the little rectangle on top then the answer is 6m.

Step-by-step explanation:

The length of the smaller object is 1m, the height is 2m, and the width is 3m (as seen to the right side near the bigger block).

Multiply all those numbers together (1×2=2, 2×3=6 or just simply 1×2×3=6)

5 0

3 years ago

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A circle is inscribed in a square. Write and simplify an expression for the ratio of the area of the square to the area of the c

STALIN [3.7K]

Best Answer: So first we need both areas, then we can relate them, and then divide the circle by the square:

A(circle) = πr^2
A(square) = L*W or (2r)*(2r) which is (2r)^2

For the square, we know this is true because because the radius is half the diameter, so if we multiply the radius by 2, we get the length of one side of the square. We also know that the lengths of both sides of the square are the same by definition of a square.

Ratio: (πr^2)/(4r^2) = π/4

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3 years ago

Of the entering class at a college, % attended public high school, % attended private high school, and % were home schoole

Veronika [31]

Answer:

(a) The probability that the student made the Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

A = a student attended public high school

B = a student attended private high school

C = a student was home schooled

D = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

$P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})$

Compute the probability that the student made the Dean's list as follows:

$P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)$

$=(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655$

Thus, the probability that the student made the Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D)}$

$=\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411$

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

$P(C^{c}|D^{c})=1-P(C|D^{c})$

$=1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185$

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

3 0

3 years ago

The sum of the angle measures of a polygon with n sides is 1260. find n.

Murrr4er [49]

Knowing the interior angle sum formula is;

180x(n-2)

180x(n-2)=1260 (solve for n here)
180n-360=1260
180n=1260+360
180n=1620
n=1620/180
n=9

Therefore, this polygon has 9 sides.

Hope I helped :)

4 0

3 years ago

Plz help me with this problem

zvonat [6]

Answer:

what is the problem

Step-by-step explanation:

7 0

3 years ago

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