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mrs_skeptik [129]
4 years ago
8

An iceberg has a volume of 0.1642 ML. What is the mass of the ice(in kg) composing the iceberg( at 0o C)? The density of ice at

0o C is 0.917g/cm^3
Chemistry
1 answer:
slega [8]4 years ago
5 0

Answer:

1.5x10¯⁴Kg

Explanation:

Data obtained from the question include the following:

Volume = 0.1642mL = 0.1642cm³

Density = 0.917g/cm³

Mass =.?

The Density of a substance is simply defined as the mass per unit volume of the substance. Mathematically, it is represented as:

Density = Mass /volume

With the above formula, we can calculate the mass of the ice as follow:

0.917 = Mass / 0.1642

Cross multiply

Mass = 0.917 x 0.1642

Mass = 0.151g

Finally, we shall convert 0.1506g to kg. This is illustrated below:

1000g = 1k

Therefore, 0.151g = 0.151/1000 = 1.5x10¯⁴Kg

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Calculate the percent composition by mass of the following compounds that are important starting materials for synthetic polymer
notsponge [240]

Answer:

C₃H₄O₂ → 50% C; 5.5 % H; 44.5% O

C₄H₆O₂ → 56 % of C; 7 % of H; 37% of O

C₃H₃N → 68 % of C; 6 % of H; 26 % of N

Explanation:

We determine the molar mass of each compound:

C₃H₄O₂ → 72 g/mol

In 1 mol of acrylic acid (72 g), we have:

3 moles of C → 12 g/mol . 3 mol = 36 g of C

4 moles of H → 1 g/mol . 4 mol = 4 g of H

2 moles of O → 16g/mol . 2 mol = 32 g of O

Then in 100 g of salt, we may have:

100 . 36 / 72 = 50 % of C

4 . 100 / 72 = 5.5 % of H

32 . 100 / 72 = 44.5 % of O

C₄H₆O₂ → 86 g/mol

In 1 mol of methyl acrylate (86 g), we have:

4 moles of C → 12 g/mol . 4 mol = 48 g of C

6 moles of H → 1 g/mol . 6 mol = 6 g of H

2 moles of O → 16g/mol . 2 mol = 32 g of O

Then in 100 g of salt, we may have:

100 . 48 / 86 = 56 % of C

6 . 100 / 86 = 7 % of H

32 . 100 / 86 = 37 % of O

C₃H₃N → 53 g/mol

In 1 mol of acrylonitrile (53 g), we have:

3 moles of C → 12 g/mol . 3 mol = 36 g of C

3 moles of H → 1 g/mol . 3 mol = 3 g of H

1 mol of N → 14g/mol . 1 mol = 14 g of N

Then in 100 g of salt, we may have:

100 . 36 / 53 = 68 % of C

3 . 100 / 53 = 6 % of H

14 . 100 / 53 = 26 % of N

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Answer:

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