Answer:
![[H^+]=1.78x10^{-8}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D1.78x10%5E%7B-8%7DM)
Explanation:
Hello there!
In this case, according to the given information about the pH, it is firstly necessary for us to remember that the pH is defined as the potential of the hydrogen ions in the solution and the concentration of those ions represents how many of them are present in the solution; in such a way, it is possible for us use:
![pH=-log([H^+])](https://tex.z-dn.net/?f=pH%3D-log%28%5BH%5E%2B%5D%29)
Whereas the concentration of hydrogen ions can be calculated as follows:
![[H^+]=10^{-pH}](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D10%5E%7B-pH%7D)
So we plug in the given pH to obtain:
![[H^+]=10^{-7.75}=1.78x10^{-8}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D10%5E%7B-7.75%7D%3D1.78x10%5E%7B-8%7DM)
Regards!
Answer:
0.26 mol
Explanation:
using general gas equation
PV=nRT
V=4.1litre= 4.1 dm³
P= 1.78 atm
R= 0.0821
PUT VALUES
The rows are known as PERIODS and the columns are know as GROUPS.
Answer:
The rate law is [B]
Explanation:
In Trials 1 and 2, the concentration of B changes and A is the same so you can see how changes in B affect the rate. In this case, 0.300/0.150=2 and 7.11 x 10^-4 / 3.56 x 10^-4= 2. Since there 2^1=2, we can say that the reaction order of B is 1.
Similarly, if we look at trials 2 and 3, the concentration of B is constant, while A is changing. In this case, the rate has not changed at all with a change in concentration of A, so this means that A has 0 order.
Therefore, the rate law is just [B].
Increase temperature = particle move faster
increase Concentration =more crowded so more collisions
Explanation:
when temperature increase,the particle gain kinetic energy which make the particles move faster hence more collisions.
if concentration increase,there will be more frequent collisions between the particles due to crowded
