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3 years ago

The bouncing of light when is changes media is called what

2 answers:

4 0

Reflection of light because it is bouncing.
Refraction is when the speed of light changes when changing mediums with different densities.

USPshnik [31]3 years ago

3 0

IT will be Refraction of light

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Plz help. I just need someone to check answer. :(

My name is Ann [436]

These substances can be separated by distillation, so your answer is A.

5 0

3 years ago

How many moles of Al would be produced from 20 moles of Al2O3?<br> 2Al2O3<br> -><br> 4A1 + 302

Evgesh-ka [11]

<h3>Answer:</h3>

$\displaystyle 40 \ mol \ Al$

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2Al₂O₃ → 4Al + 3O₂

[Given] 20 mol Al₂O₃

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Al₂O₃ → 4 mol Al

<u>Step 3: Stoich</u>

[DA] Set up: $\displaystyle 20 \ mol \ Al_2O_3(\frac{4 \ mol \ Al}{2 \ mol \ Al_2O_3})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 40 \ mol \ Al$

<u>Step 4:Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

Since our final answer already has 1 sig fig, there is no need to round.

4 0

3 years ago

A runner travels at a constant speed of 4 m/s. What happens to the velocity of the runner when the runner changes direction?

ANTONII [103]

Answer:

4m/s in the direction of the turn

Explanation:

The velocity of an object is the rate of change of its position with respect to a frame of reference.

Assuming the runner stays the same speed as he turns, his velocity will be 4m/s in the speed he turns.

5 0

3 years ago

Please help me with this question!!

mestny [16]

Answer: 824.6 g of NaCl are produced from 500.0 g of chlorine.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$ $\text{Moles of} Cl_2=\frac{500.00g}{71g/mol}=7.04moles$

$2Na+Cl_2\rightarrow 2NaCl$

According to stoichiometry :

1 mole of $Cl_2$ produce = 2 moles of $NaCl$

Thus 7.04 moles of $Cl_2$ will produce= $\frac{2}{1}\times 7.04=14.08moles$ of $NaCl$

Mass of $NaCl=moles\times {\text {Molar mass}}=14.08moles\times 58.5g/mol=824.26g$

Thus 824.6 g of NaCl are produced from 500.0 g of chlorine.

3 0

3 years ago

For the combustion reaction of C9H12 in O2: how many moles of O2 is required to react with 0.67 mol C9H12?

miskamm [114]

Answer:

8.0 mol O₂

Explanation:

Let's consider the complete combustion reaction of C₉H₁₂.

C₉H₁₂ + 12 O₂ → 9 CO₂ + 6 H₂O

The molar ratio of C₉H₁₂ to O₂ is 1:12. The moles of O₂ required to react with 0.67 moles of C₉H₁₂ are:

0.67 mol C₉H₁₂ × (12 mol O₂/1 mol C₉H₁₂) = 8.0 mol O₂

8.0 moles of O₂ are required to completely react with 0.67 moles of C₉H₁₂.

7 0

3 years ago

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