1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Karolina [17]
4 years ago
12

Which of the following equations is balanced in an acidic solution?

Chemistry
1 answer:
AURORKA [14]4 years ago
5 0
The answer
the only equation which is balanced  in an acidic solution is
<span>D. SO42- + 4H+ + 2e- ------------------  SO2(g) + 2H2O(l)
proof:
it is an acid solution because we can see H+, presence of acid in solution
</span><span>A. SO42- + 2H2O(l) + 2e- SO2(g) + 4OH- 
B. SO42- + 4H+ SO2(g) + 4OH- + 2H2O(l) are basic solution, cause we can observe on these solutions the presence of OH-, 
as for </span><span>SO42- + 2e- --------------------SO2(g)    it is not an acid solution</span>
You might be interested in
What is the mole fraction of acetic acid in a solution containing 2 moles of vinegar and 3 moles of water? A. 2 B. 3 C. 0.4 D. 0
9966 [12]

Answer:

C. 0.4.

Explanation:

<em>∵ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) = (no. of moles acetic acid)/(no. of moles of acetic acid + no. of moles of water).</em>

<em></em>

- no. of moles of acetic acid = 2, no. of moles of water = 3.

- Total no. of moles = no. of moles of acetic acid + no. of moles of water = 2 + 3 = 5.

<em>∴ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) =</em> (2)/(5)<em> = 0.4.</em>

3 0
3 years ago
Read 2 more answers
In the presence of oxygen, the three-carbon compound pyruvate can be catabolized in the citric acid cycle. First, however, the p
Flura [38]

Answer:1.

Explanation: This reaction is catalyzes by pyruvate dehydrogenase. Pyruvate being the end product of glycolysis has many fates after glycolysis,one of which is to enter the TCA(Tricarboxylic acid cycle) cycle. It is first converted to actetate by the action of pyruvate dehydrogenase. This enzyme converts pyruvate to acetate releasing CO2 and NADH because this oxidative decarboxylation of pyruvate is coupled with reduction of NAD+ which can feed into the electron transport chain.

6 0
3 years ago
Kc is 1.67 × 1020 at 25°C for the formation of iron(III) oxalate complex ion: Fe3+(aq) + 3 C2O42-(aq) ⇌ [Fe(C2O4)3]3-(aq). If 0.
AleksandrR [38]

Answer:

hello? are you still here? reply if you are

8 0
3 years ago
What type of energy is stored within a chemical substance?
s2008m [1.1K]
<span>Chemical Energy is energy stored in the bonds of chemical compounds (atoms and molecules). It is released in a chemical reaction, often producing heat as a by-product (exothermic reaction). Batteries, biomass, petroleum, natural gas, and coal are examples of stored chemical energy and NO i didnt get this off google</span>
4 0
3 years ago
Read 2 more answers
The density of potassium, which has the BCC structure, is 0.855 g/cm3. The atomic weight of potassium is 39.09 g/mol. Calculate
Delicious77 [7]

<u>Answer:</u>

<u>For a:</u> The edge length of the crystal is 533.5 pm

<u>For b:</u> The atomic radius of potassium is 231.01 pm

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the lattice parameter or edge length of the crystal, we use the equation:

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density = 0.855g/cm^3

Z = number of atom in unit cell = 2  (BCC)

M = atomic mass of metal = 39.09 g/mol

N_{A} = Avogadro's number = 6.022\times 10^{23}

a = edge length of unit cell = ?

Putting values in above equation, we get:

0.855=\frac{2\times 39.09}{6.022\times 10^{23}\times (a)^3}\\\\\a=5.335\times 10^{-8}cm=533.5pm

<u>Conversion factor:</u>  1cm=10^{10}pm

Hence, the edge length of the crystal is 533.5 pm

  • <u>For b:</u>

To calculate the edge length, we use the relation between the radius and edge length for BCC lattice:

R=\frac{\sqrt{3}a}{4}

where,

R = radius of the lattice = ?

a = edge length = 533.5 pm

Putting values in above equation, we get:

R=\frac{\sqrt{3}\times 533.5}{4}=231.01pm

Hence, the atomic radius of potassium is 231.01 pm

4 0
3 years ago
Other questions:
  • The electron configuration can also be represented by writing the symbol for the occupied subshell and adding a superscript to i
    10·1 answer
  • Suppose 7 pints of a 23​% alcohol solution is mixed with 3 pints of a 70​% alcohol solution. what is the concentration of alcoho
    12·1 answer
  • How plastic polymer types of compositions, surface hydrophobicity, crystallinity, porosity, size, shapes, aging or degree of wea
    10·1 answer
  • Which of these best describes why water molecule is polar?
    9·1 answer
  • What is the percent composition of hydrogen in a compound if the mass of the initial compound is 276 gram and the mass of collec
    8·1 answer
  • Consider the reaction cacn2 3 h2o → caco3 2 nh3 . how much nh3 is produced if 187 g of caco3 are produced?
    9·1 answer
  • The energy of a non-covalent interaction is dependent on their range. Organize the following types of non-covalent interactions
    13·1 answer
  • 1.How many moles of each element are in 0.0250 mol of K 2 Cr O 4? 2. How many moles of ammonium ions are in 4.50 mol of (N H 4 )
    11·1 answer
  • How are stars and comets different?
    11·1 answer
  • what is the suggested weight of the sample that should be disssolved in the beaker before it is transferred to the NMR tube
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!