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Karolina [17]
3 years ago
12

Which of the following equations is balanced in an acidic solution?

Chemistry
1 answer:
AURORKA [14]3 years ago
5 0
The answer
the only equation which is balanced  in an acidic solution is
<span>D. SO42- + 4H+ + 2e- ------------------  SO2(g) + 2H2O(l)
proof:
it is an acid solution because we can see H+, presence of acid in solution
</span><span>A. SO42- + 2H2O(l) + 2e- SO2(g) + 4OH- 
B. SO42- + 4H+ SO2(g) + 4OH- + 2H2O(l) are basic solution, cause we can observe on these solutions the presence of OH-, 
as for </span><span>SO42- + 2e- --------------------SO2(g)    it is not an acid solution</span>
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Answer:

Density = 2.7 \ g/cm^3

Explanation:

The equation for density is:

Density = \frac{mass}{volume}

We can plug the given values into the equation:

Density = \frac{81\ g}{30.0\ cm^2}

Density = 2.7 \ g/cm^3

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2 years ago
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Answer:

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Reacciones acido base

HCl + NaOH → NaCl + H2O.

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HCl + NH3 → NH4Cl + H2O.

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Explanation:

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3 0
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Read 2 more answers
3.65 gram of hcl is dissolved in 180 gram of water. Find the total number of molecules of hydrogen​
Morgarella [4.7K]

Answer:

Molec_{\ H_{tot}}=1.206x10^{25}molec

Explanation:

Hello.

In this case, taking into account that HCl has one molecule of hydrogen per mole of compound which weights 36.45 g/mol, we compute the number of molecules of hydrogen in hydrochloric acid by considering the given mass and the Avogadro's number:

molec_{\ H}=3.65gHCl*\frac{1molHCl}{36.45gHCl} *\frac{1molH}{1molHCl}*\frac{6.022x10^{23}molec_\ H}{1molH}  =6.03x10^{22}molec

Now, from the 180 g of water, we see two hydrogen molecules per molecule of water, thus, by also using the Avogadro's number we compute the molecules of hydrogen in water:

molec_{\ H}=180gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O}*\frac{6.022x10^{23}molec_\ H}{1molH}  =1.20x10^{25}molec

Thus, the total number of molecules turns out:

Molec_{\ H_{tot}}=6.03x10^{22}+1.20x10^{25}\\\\Molec_{\ H_{tot}}=1.206x10^{25}molec

Regards.

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Answer: b

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