Answer:
3.974 Joule
Explanation:
Diameter of ring = 7.7 cm
a = Distance from the center = d/2 = 3.85 cm = 0.0385 m
Q = Charge = 5 mC
q = Charge to move = 3.4 mC
k = Coulomb constant = 9×10⁹ Nm²/C²
Work done will be equal to Potential energy when mass is at center
∴ Work to move a tiny 3.4 mC charge from very far away to the center of the ring is 3.974 Joule
Answer:
0.2s
force = change in momentum/ time
time = change in momentum/time
Explanation:
first, let's find the change in momentum
pf-pi
5×(-2) - 5× 2
-20kgm/s = 20kgm/s(by changing the direction of whole system)
time = change in momentum/time
20/100
<u> 0.2s</u>
Answer:
M= -0.51
Explanation:
After i calculated my v to be -5.2cm from the formula 1/f=1/v+1/u
Then m=v/u which is -0.51
Answer:
Fnet = 0
Explanation:
- Since the block slides across the floor at constant speed, this means that it's not accelerated.
- According Newton's 2nd Law, if the acceleration is zero, the net force on the sliding mass must be zero.
- This means that there must be a friction force opposing to the horizontal component of the applied force, equal in magnitude to it:
- In the vertical direction, the block is not accelerated either, so the sum of the normal force and the vertical component of the applied force, must be equal in magnitude to the force of gravity on the block:
⇒ 169 N + Fn = Fg = 216 N (3)
- This means that there must be a normal force equal to the difference between Fappy and Fg, as follows:
- Fn = 216 N - 169 N = 47 N (4)
Answer:
Yes because while you slide down the slide you are obviously going to wear clothes and the cotton on your clothes rubbing up against that rubber from the slides, are gonna react by sending a static electricity shock feeling to your body
Explanation:
