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sashaice [31]
4 years ago
13

Which direction is the force of friction?

Physics
2 answers:
algol [13]4 years ago
8 0
B, friction always acts opposite
liraira [26]4 years ago
3 0

Friction always acts opposite to the motion.<em>  (B)</em>

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A ring of diameter 7.70 cm is fixed in place and carries a charge of 5.00 mC uniformly spread over its circumference. (a) How mu
MatroZZZ [7]

Answer:

3.974 Joule

Explanation:

Diameter of ring = 7.7 cm

a = Distance from the center = d/2 = 3.85 cm = 0.0385 m

Q = Charge = 5 mC

q = Charge to move = 3.4 mC

k = Coulomb constant = 9×10⁹ Nm²/C²

Work done will be equal to Potential energy when mass is at center

U=\frac{kQq}{a}\\\Rightarrow U=\frac{9\times 10^9\times 5\times 10^{-6}\times 3.4\times 10^{-6}}{0.0385}=3.974\ J

∴ Work to move a tiny 3.4 mC charge from very far away to the center of the ring is 3.974 Joule

4 0
3 years ago
Read 2 more answers
a 2kg ball moving at speed 5m/s hits a wall .the force exerted by the wall on the ball is 100n .if the collision is perfectly el
levacccp [35]

Answer:

0.2s

force = change in momentum/ time

time = change in momentum/time

Explanation:

first, let's find the change in momentum

pf-pi

5×(-2) - 5× 2

-20kgm/s = 20kgm/s(by changing the direction of whole system)

time = change in momentum/time

               20/100

                 <u> 0.2s</u>

4 0
3 years ago
An object is placed at 10.2 cm in front of a diverging lens with a focal length of -10.6 cm. What is the magnification
adoni [48]

Answer:

M= -0.51

Explanation:

After i calculated my v to be -5.2cm from the formula 1/f=1/v+1/u

Then m=v/u which is -0.51

7 0
4 years ago
You pull with a force of 295 N on a rope that is attached to a block of mass 22 kg, and the block slides across the floor at a c
Sergeeva-Olga [200]

Answer:

Fnet = 0

Explanation:

  • Since the block slides across the floor at constant speed, this means that it's not accelerated.
  • According Newton's 2nd Law, if the acceleration is zero, the net force on the sliding mass must be zero.
  • This means that there must be a friction force opposing to the horizontal component of the applied force, equal in magnitude to it:

       F_{appx} = F_{app} * cos \theta = 295 N * cos 35 = 242 N  (1)

  • In the vertical direction, the block is not accelerated either, so the sum of the normal force and the vertical component of the applied force, must be equal in magnitude to the force of gravity on the block:

      F_{appy} = F_{app} * cos \theta = 295 N * sin 35 = 169 N  (2)

⇒    169 N + Fn = Fg = 216 N  (3)

  • This means that there must be a normal force equal to the difference between Fappy and Fg, as follows:
  • Fn = 216 N - 169 N = 47  N (4)

6 0
3 years ago
Have you ever felt a shock sliding down a plastic slide (like in a McDonald’s Play Place)? Do you think this is related to elect
Aleksandr [31]

Answer:

Yes because while you slide down the slide you are obviously going to wear clothes and the cotton on your clothes rubbing up against that rubber from the slides, are gonna react by sending a static electricity shock feeling  to your body  

Explanation:

6 0
3 years ago
Read 2 more answers
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