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2 years ago

The peak magnetic field strength in a residential microwave oven is 9. 2 x 10-5 t. what is the intensity of the microwave?

Physics

1 answer:

Alexandra [31]2 years ago

7 0

The intensity of the microwave is 10.09 × 10⁵ W/m².

The unit of magnetic induction is the tesla (T). The magnetizing force, which induces the lines of force through a material, is called the field intensity, H (or H-field), and by convention has the units ampere per meter (A m−1) .

The portion of a material's magnetic field that results from an external current and is not intrinsic to the material itself is known as the magnetic field strength, also known as magnetic intensity or magnetic field intensity. It is measured in amperes per meter and represented as the vector H.

Magnetic Field, B = 9.2 × 10⁻⁵ T

$I_{avg} = \frac{CB_0^2}{2\mu _0}$

$= \frac{(2.998*10^8 m/s) (9.2 * 10^-^5 T)^2}{2 ( 4\pi * 10^-^7)}$

$= 10.09$ × $10^5 \frac{W}{m^2}$

Therefore, the intensity of the microwave is 10.09 × 10⁵ W/m².

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Answer:

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3 years ago

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The potential energy at x = 8 m is -2000 V and at x = 2 m is 400 V. What is the magnitude and direction of the electric field?

Stells [14]

The potential energy at x = 8 m is -2000 V and at x = 2 m is 400 V. The magnitude and direction of the electric field will be 400 V/m directed parallel to the +x-axis

Electric field, an electric property associated with each point in space when charge is present in any form. The magnitude and direction of the electric field are expressed by the value of E, called electric field strength or electric field intensity or simply the electric field.

The electric potential energy of any given charge or system of changes is termed as the total work done by an external agent in bringing the charge or the system of charges from infinity to the present configuration without undergoing any acceleration.

The relation between electric field and electric potential can be generally expressed as – “Electric field is the negative space derivative of electric potential.”

Electric field = - d V / dx

-(-2000-400) = $\int\ {E} \, dx$

2400 = E (8-2)

2400 V = E (6)

E = 400 V/m

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2 years ago

Which of the following objects has the greatest kinetic energy?

Verizon [17]

Answer:

a baseball flying through the air at 90 miles per hour

Explanation:

For the question, Therefore, the kinetic energy of an object is proportional to the square of its velocity (speed). In other words, If the velocity is doubled the kinetic energy will increase by a factor of four.

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4 years ago

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A force of 6 N acts on a 33 kg object for 9 seconds. What is the objects change in velocity?

GuDViN [60]

Acceleration = change in velocity/time
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3 years ago

To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle wi

Gnom [1K]

Answer:

(a) Acceleration of positron is 6.03 x 10¹³ m/s²

(b) Speed of positron after 8.70 x 10⁻⁹ s is 5.24 x 10⁵ m/s

Explanation:

Given :

Constant electric field, E = 343 N/C

Mass of positron, m = 9.1 x 10⁻³¹ kg

Charge of positron, q = +e = 1.6 x 10⁻¹⁹ C

(a) Coulomb force on the positron is determine by the relation :

F = q x E ....(1)

But, force is also equals to product of mass and acceleration. So,

F = ma .....(2)

Here a is acceleration.

From equation (1) and (2).

m x a = q x E

$a=\frac{qE}{m}$

Substitute the values of q, E and m in the above equation.

$a=\frac{1.6\times10^{-19}\times 343}{9.1\times10^{-31} }$

a = 6.03 x 10¹³ m/s²

(b) Initially, the positron is at rest, so its initial speed is zero.

The equation of motion for positron is :

v = u + at

Here v is final speed, u is initial speed and t is time.

Since, u is zero, so the equation becomes :

v = at

Substitute 8.70 x 10⁻⁹ s for t and 6.03 x 10¹³ m/s² for a in the above equation.

v = 6.03 x 10¹³ x 8.70 x 10⁻⁹ m/s

v = 5.24 x 10⁵ m/s

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