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1 year ago

The peak magnetic field strength in a residential microwave oven is 9. 2 x 10-5 t. what is the intensity of the microwave?

Physics

1 answer:

Alexandra [31]1 year ago

7 0

The intensity of the microwave is 10.09 × 10⁵ W/m².

The unit of magnetic induction is the tesla (T). The magnetizing force, which induces the lines of force through a material, is called the field intensity, H (or H-field), and by convention has the units ampere per meter (A m−1) .

The portion of a material's magnetic field that results from an external current and is not intrinsic to the material itself is known as the magnetic field strength, also known as magnetic intensity or magnetic field intensity. It is measured in amperes per meter and represented as the vector H.

Magnetic Field, B = 9.2 × 10⁻⁵ T

$I_{avg} = \frac{CB_0^2}{2\mu _0}$

$= \frac{(2.998*10^8 m/s) (9.2 * 10^-^5 T)^2}{2 ( 4\pi * 10^-^7)}$

$= 10.09$ × $10^5 \frac{W}{m^2}$

Therefore, the intensity of the microwave is 10.09 × 10⁵ W/m².

Learn more about intensity here:

brainly.com/question/24319848

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A 45 kg wagon is being pulled with a rope that makes an angle of 38 degrees with the horizontal. The applied force is 410 N and

mel-nik [20]

Answer:

7.35m/s²

Explanation:

From the question we are not told what to find but we can as well find the acceleration of the wagon.

According to newton second law of motion

$\sum F_x = ma_x\\Fm - Ff = ma_x\\Fm - \mu R = ma_x\\Fm- \mu mg = ma_x\\$

Fm is the moving force = 410N

$\mu$ is the coefficient of friction = 0.18

m is the mass = 45kg

g is the acceleration dur to gravity = 9.8m/s²

a is the acceleration of the wagon

Substitute the given data into the equation ang get ax

$Fm- \mu mg = ma_x\\410 - (0.18)(9.8)(45) = 45a_x\\410 - 79.38 = 45a_x\\330.62 = 45a_x\\a_x = 330.62/45\\a_x = 7.35m/s^2\\$

Hence the acceleration of the wagon is 7.35m/s²

8 0

3 years ago

Can anyone tell me the ans of this question also please

Dmitry_Shevchenko [17]

Answer:

Hey there!

Stopwatch X recorded 40 seconds, and stopwatch Y recorded 50 seconds.

Stopwatch Y recorded 10 seconds longer than stopwatch X.

Hope this helps :)

6 0

3 years ago

Read 2 more answers

When Arti kicks a football, two forces interact. Arti's foot exerts a force on the ball. What exerts a force on Arti's foot?

vagabundo [1.1K]

The football and air resistance between contact

7 0

3 years ago

One billiard ball is shot east at 2.2 m/s. A second, identical billiard ball is shot west at 0.80 m/s. The balls have a glancing

Leona [35]

Answer:

(a). The speed of the first ball after the collision is 1.95 m/s.

(b). The direction of the first ball after the collision is 44.16° due south of east.

Explanation:

Given that,

Velocity of one ball u₁= 2.2i m/s

Velocity of second ball u₂=- 0.80i m/s

Final velocity of the second ball v₂= 1.36j m/s

The mass of the identical balls are

$m = m_{1}=m_{2}$

(a). We need to calculate the speed of the first ball after the collision

Using law of conservation of momentum

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}$

Along X- axis

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}$

$v_{1}=u_{1}+u_{2}$

Put the value into the formula

$v_{1}=2.2i-0.80i$

$v_{1}=1.4i\ m/s$

Along Y-axis

$0=m_{1}v_{1}+m_{2}v_{2}$

$m_{1}v_{1}=-m_{2}v_{2}$

$v_{1}=-v_{2}$

Put the value into the formula

$v_{1}=-1.36j\ m/s$

Then the final speed of the first ball

$v_{1}=\sqrt{(1.4)^2+(1.36)^2}$

$v_{1}=1.95\ m/s$

(b) We need to calculate the direction of the first ball after the collision

Using formula of direction

$\tan\theta=\dfrac{v_{2}}{v_{1}}$

$\tan\theta=\dfrac{-1.36}{1.4}$

$\theta=\tan^{-1}\dfrac{-1.36}{1.4}$

$\theta=-44.16^{\circ}$

Negative sign shows the direction of first ball .

Hence, (a). The speed of the first ball after the collision is 1.95 m/s.

(b). The direction of the first ball after the collision is 44.16° due south of east.

7 0

3 years ago

Why is traveling between the stars (by creatures like us) difficult?

mariarad [96]

Answer:

Stars are at large distances that even light takes thousands of years to reach us from there.

for example, alpha centauri is 4300 light years away from earth and it is considered the nearest star to us, this means that light from there takes 4300 years to reach us and with a spaceships that can move with the speed of light is would take us 4300 years to get there which is imposible to live for that long.

hence, it is difficult to move between the stars.

4 0

3 years ago